Answer:
Below in bold.
Step-by-step explanation:
x can have any real value - the domain is (-∞, ∞).
f(x) cannot be 0 or negative, no matter how negative x is, - the range is (0, ∞)
<span> (6q+7)(2q+3)
12q^2 + 18q + 14q + 21
12q^2 + 32q + 21</span>
Answer:
x^2 +2x +4
x^2 +2x +(2/2)^2-(2/2)^2+4
(x+1)^2-1+4
(x+1)^2+3=0
(x+1)^2= -3
(x+1)= ±√-3
Since a negative number cannot be square rooted,
there are no solutions to this equation.
Hope this helps:)
Answer:
do a line conforming to the table days=x sales =y
Step-by-step explanation:
