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NeTakaya
2 years ago
11

PLS HELP! What is the value of x in the figure? Enter your answer in the box. x =

Mathematics
2 answers:
Lelu [443]2 years ago
8 0

Answer:

x=29 degrees

Step-by-step explanation:

Both angles shown ad up to a 90 degree angle. We can see this because on the adjacent side there is a box indicating that it is a right angle. The three angles add up to 180, thus if we subtract 90 degrees due to the angle on the left of the y axis, the angles on the right of the y axis must add up to 90 as well.

Since the angles on the right must add up to 90, we set an equation to solve for x:

61+x=90(subtract 61)

x=29 degrees

Veronika [31]2 years ago
3 0

We need to do 90-61, which is 29. X = 29, because the base of 61 and the right of the x is equal to a right angle.

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Add. Simplify the answer and write it as a mixed number. 1/2+2/3+1/6
lyudmila [28]

Answer:

1 1/3

Step-by-step explanation:

Find the common denominator of all three which is 6.

Then multiply each to make the common denominator 6

1/2*3 = 3/6

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Then add all of them together

3/6+4/6+1/6 = 1 2/6

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3 years ago
Use the number line below, where RS = 7y +5. ST = 3y +5, and RT = 70.<br> a. What is the value of y?
NeTakaya

Answer:

Step-by-step explanation:

7y+5+3y+5=70

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y=6

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8 0
3 years ago
What is the answer? ​
Dimas [21]

Answer:

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Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
How do I solve this type of problem? I'm trying to find both missing values. Please explain how to solve this as thoroughly as y
goldenfox [79]
Hi there! 

In order to solve, we'll need to use a proportion: 20/a = 21/20. Then, we'll cross-multiply and solve to find a: 21a = 400 | a = 19.05. Next, to find b, we can just use pythagorean theorem: 20^2 + (400/21)^2 = b^2 | b = 27.62.
We are using geometric mean to solve for a, then using pythagorean theorem to solve for b. If you need more help with geometric mean, or would like a complete explanation, please let me know! I'd be happy to provide you with that information.

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
3 0
3 years ago
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