<span>The sum of two numbers is 48.
a + b = 48
;
If one third of one number is 5 greater than one sixth of another number,
a = b + 5
multiply both sides by 6, cancel the fractions
2a = b + 30
2a - b = 30
</span><span>use elimination to solve this
a + b = 48
2a - b =30
-------------Addition eliminates b, find a
3a = 78
a =
a = 26
then
26 + b = 48
b = 48 - 26
b = 22</span>
Answer:
I'm glad you asked!
Step-by-step explanation:
OK,let's simplify the number for a equivalent expression.

Distribute:


Combine Like Terms:



The Final Answer is : 
We know that
[scale factor]=1/2
[dilated area of circle]=[original area of circle]*[scale factor]²
so
[dilated area of circle]=[original area of circle]*[1/2]²
[dilated area of circle]=[original area of circle]*[1/4]
therefore
the answer is
<span>The area will be 1/4 the original</span>
Answer: (3) f(8) = g(8)
<u>Step-by-step explanation:</u>
Let's compare the values of f(x) and g(x) when x = 0, 2, 8, and 4
<u> f(x) </u> <u> g(x) </u> <u>Comparison</u>
f(x) = 2x - 3 
f(0) = 2(0) - 3 
= -3 = 1 f(0) < g(0)
f(2) = 2(2) - 3 
= 1 = 4 f(2) < g(2)
f(8) = 2(8) - 3 
= 13 = 13 f(8) = g(8)
f(4) = 2(4) - 3 
= 5 = 7 f(4) < g(4)
The only statement provided that is true is f(8) = g(8)
Answer:DON'T KNOW SO DON'T LOOK AT ME
Step-by-step explanation: