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3 years ago

11

There is a point on a coordinate plane at (5,0). There is another point at (-3,0). what is the distance between these two points

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HELP!!!!!!!

1 answer:

zloy xaker [14]3 years ago

3 0

Answer:

The distance between the points is 8.

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I am an odd 4-digit number between 5,000 and 5,999. The digit in the thousands place is half

Shkiper50 [21]

You are 5,987. 5 in the thousands place because you are a number in the 5,000s, and also the smallest 2 digit number divided 2 makes 5. 9 in the hundreds place because the biggest 1 digit number is 9. 8 in the tens place because the only single digit number that is a multiple of 4, but not 4, is 8. 7 in the ones place because 9 is the hundreds place, minus 2 is 7.

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3 years ago

(1 point) In 7 years Harry and Sally would like to have $14000 for a down payment on a house. How much should they deposit each

den301095 [7]

Answer:

$110.37

Step-by-step explanation:

Assuming the monthly payment is made at the beginning of the month, the formula for the monthly payment P that gives future value A will be ...

... A = P(1+r/12)((1+r/12)^(nt) -1)/(r/12) . . . . n=compoundings/year, t=years

... 14000 = P(1+.11/12)((1+.11/12)^(12·7) -1)/(.11/12)

... 14000 = P(12.11)((1+.11/12)^84 -1)/0.11 ≈ P·126.84714 . . . . fill in the given values

... P = 14000/126.84714 = 110.37 . . . . . divide by the coefficient of P

They should deposit $110.37 at the beginning of each month.

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3 years ago

Teenagers signed up to be subjects in a psychology experiment. When they arrive

stealth61 [152]

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2 years ago

Y > 2 A: [2,[infinity]] B: (2,[infinity]] C: (2,[infinity]) D: [2,[infinity])

Ulleksa [173]

Answer:

B: (2,[infinity]]

Step-by-step explanation:

because you will take all numbers bigger than 2 but 2 is not included

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3 years ago

I need the answer for this problem please

Savatey [412]

Answer:

B

Step-by-step explanation:

Find all probabilities:

A. False

$Pr(\text{red shirt}|\text{large shirt})=\dfrac{\text{number red large shirts}}{\text{number large shirts}}=\dfrac{42}{77}=\dfrac{6}{11}\\ \\Pr(\text{large shirt})=\dfrac{\text{number large shirts}}{\text{number shirts}}=\dfrac{77}{165}=\dfrac{7}{15}$

B. True

$Pr(\text{blue shirt}|\text{large shirt})=\dfrac{\text{number blue large shirts}}{\text{number large shirts}}=\dfrac{35}{77}=\dfrac{5}{11}\\ \\Pr(\text{blue shirt})=\dfrac{\text{number blue shirts}}{\text{number shirts}}=\dfrac{75}{165}=\dfrac{5}{11}$

C. False

$Pr(\text{shirt is medium and blue})=\dfrac{\text{number medium and blue shirts}}{\text{number shirts}}=\dfrac{48}{165}=\dfrac{16}{55}\\ \\Pr(\text{medium shirt})=\dfrac{\text{number medium shirts}}{\text{number shirts}}=\dfrac{88}{165}=\dfrac{8}{15}$

D. False

$Pr(\text{large shirt}|\text{red shirt})=\dfrac{\text{number red large shirts}}{\text{number red shirts}}=\dfrac{42}{90}=\dfrac{7}{15}\\ \\Pr(\text{red shirt})=\dfrac{\text{number red shirts}}{\text{number shirts}}=\dfrac{90}{165}=\dfrac{6}{11}$

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3 years ago