Explanation: Let AB is tree of height h
t
=
? and CD is Tonya h
g
=
1.3 meter tall at A
C
= 7 meters in front of tree . The shadow C
E
=
1.8 meters long . So two similar triangles are formed , one Δ
A
E
B and other Δ
C
E
D
. So A
B
C
D
=
A
E
C
E or h
t
h
g
=
A
E
A
C or h
t
h
g
=
A
C
+
C
E AC or h
t 1.3
=
7
+
1.8
1.8 or h
t
=
8.8
⋅
1.3
1.8
≈
6.36
(
2
d
p
)m
