The tension does no (zero) work
F· S = W
Since the tension is perpendicular to the direction of motion, and there is no change in S the work done is zero.
Answer:
assume nitrogen is an ideal gas with cv=5R/2
assume argon is an ideal gas with cv=3R/2
n1=4moles
n2=2.5 moles
t1=75°C <em>in kelvin</em> t1=75+273
t1=348K
T2=130°C <em>in kelvin</em> t2=130+273
t2=403K
u=пCVΔT
U(N₂)+U(Argon)=0
<em>putting values:</em>
=>4x(5R/2)x(Tfinal-348)=2.5x(3R/2)x(T final-403)
<em>by simplifying:</em>
Tfinal=363K
The electric field inside a parallel plate capacitor is given by:
E = Q/(ε₀A)
E is the electric field, Q is the charge stored on one of the plates, and A is the area of one of the plates.
The plates are circular, so the area A of one of the plates is given by:
A = πr²
where r is the radius.
Therefore the electric field is given by:
E = Q/(ε₀πr²)
Given values:
E = 3×10⁶N/C (max E field allowed before breakdown occurs)
r = 54×10⁻²m
Plug in these values and solve for Q:
3×10⁶ = Q/(ε₀π(54×10⁻²)²)
Q = 2.4×10⁻⁵C