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3 years ago

What amount of force is needed to propel and object of 27 kg to an acceleration of 11,550 m/s^2?

Physics

1 answer:

madreJ [45]3 years ago

5 0

Answer:

311,850 N

Explanation:

We can solve the problem by using Newton's second law:

$F=ma$

where

F is the net force exerted on the object

m is the mass of the object

a is the acceleration

In this problem, we have

m = 27 kg is the mass

a = 11,550 m/s^2 is the acceleration

Solving for F, we find:

$F=(27)(11550)=311,850 N$

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Read 2 more answers

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Answer:

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Unknown:

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3 years ago

As a glacier melts, the volume V of the ice, measured in cubic kilometers, decreases at a rate modeled by the differential equat

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Answer:

the volume in terms of time t ⇒ $\\V = e^{0.05t} + 399\\$

Explanation:

Given that :

$\frac{dv}{dt}= kv\\\\\int\limits \, \frac{dv}{v}= \int\limits \, kdt\\In v = kt + C_1\\v = e^{kt} + C\\400 = e^{k*0} + C\\400 = 1 + C\\C = 400 -1\\C = 399$

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