Grape juice solid-conduction , solid-convection,fluid-conduction , fluid-convection

Physics

1 answer:

Gelneren [198K]2 years ago

5 0

The process by which the heat energy is transmitted between the atoms or molecules is known as conduction.

Explanation:

Conduction is the transfer of heat through the material that are caused by temperature gradient with the material ends in heat flux. The heat transfer done by movement and mixing of a fluid is known as convection.

If a fluid is taken and it is kept as stationary. If there is a temperature gradient across that fluid, there would be transfer of heat that occurs in the fluid. It is negligible when compared to convective heat transfer.

Because of the heat transfer from solid to solid, density of liquid changes and start to move in upward direction due to low density. This type of motion is known as convection currents.

You might be interested in

Which layer of the sun is seen during a total solar eclipse?

maks197457 [2]

Answer:

The Corona.

Explanation:

The Corona is the outermost part of the Sun. Usually, it is nto visible due to the light emitted by the Sun. During a total solar eclipse, that is the moon comes between the Earth and the Sun, the glowing white edge around the eclipse is the Corona.

4 0

3 years ago

You are participating in a NASA traineeship, working with a group planning a new landing on Mars. Your supervisor has come up wi

aivan3 [116]

Answer:

$h=17005.8 km$

Explanation:

Newton's law of universal gravitation states that the force experimented by a satellite of mass m orbiting Mars, which has mass $M=6.39\times10^{23} kg$ at a distance r will be:

$F=\frac{GMm}{r^2}$

where $G=6.67\times10^{-11}Nm^2/kg^2$ is the gravitational constant.

This force is the centripetal force the satellite experiments, so we can write:

$F=ma_{cp}=mr\omega^2=mr(\frac{2\pi}{T})^2=\frac{4\pi^2mr}{T^2}$

Putting all together:

$\frac{GMm}{r^2}=\frac{4\pi^2mr}{T^2}$

which means:

$r=\sqrt[3]{\frac{GM}{4\pi^2}T^2}$

Which for our values is:

$r=\sqrt[3]{\frac{(6.67\times10^{-11}Nm^2/kg^2)(6.39\times10^{23} kg)}{4\pi^2}(1.026\times24\times60\times60s)^2}=20395282m=20395.3km$

Since this distance is measured from the center of Mars, to have the height above the Martian surface we need to substract the radius of Mars R=3389.5 km , which leaves us with:

$h=r-R=20395.3km-3389.5 km=17005.8 km$