All categories

3 years ago

I just need help with two questions

Mathematics

1 answer:

ollegr [7]3 years ago

4 0

I can’t see them very well

You might be interested in

-2x+y=-12, 3y- 2x=-12

inessss [21]

Answer:

x = 6

y = 0

Explanation:

−2x+y=−12;3y−2x=−12

Rewrite equations:

−2x+y=−12;−2x+3y=−12

Solve −2x+y=−12 for y

−2x+y=−12

−2x+y+2x=−12+2x(Add 2x to both sides)

y=2x−12

Substitute 2x−12 for y in −2x+3y=−12

−2x+3y=−12

−2x+3(2x−12)=−12

4x−36=−12 (Simplify both sides of the equation)

4x−36+36=−12+36 (Add 36 to both sides)

4x=24

Divide both sides by 4

4x / 4 = 24 / 4

x = 6

Substitute 6 for x in y=2x−12

y=2x−12

y=(2)(6)−12

y=0 (Simplify both sides of the equation)

6 0

3 years ago

Read 2 more answers

Add. *

mojhsa [17]

The answer is C 5.8 x 10 ml

7 0

3 years ago

2x^2+2x-144=0 Answers?

iren [92.7K]

Answer:

x=8,-9

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Jon worked 5 hours less than 2 times jan worked total of 97 hours, so how many hours jon worked?

DedPeter [7]

10. Hours he worked this is the answer to the problem

6 0

3 years ago

NASA is conducting an experiment to find out the fraction of people who black out at G forces greater than 6 6 . In an earlier s

Xelga [282]

Answer:

The sample size must be atleast 502 to have a margin of error of 0.03

Step-by-step explanation:

We are given the following in the question:

Proportion = 0.32

$\hat{p} = 0.32$

Level of significance = 0.15

Margin of error = 0.03

Formula for margin of error =

$z_{stat}\times \sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

$z_{critical}\text{ at}~\alpha_{0.15} = 1.44$

We have to find the sample size such that the margin of error is atmost 0.03.

Putting values, we get,

$z_{stat}\times \sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\leq 0.03\\\\1.44\times \sqrt{\dfrac{0.32(1-0.32)}{n}}\leq 0.03\\\\\sqrt{n}\geq 1.44\times \dfrac{\sqrt{0.32(1-0.32)}}{0.03}\\\\\sqrt{n}\geq 22.39\\n\geq 501.3121\\\Rightarrow n\geq 502$

Thus, the sample size must be atleast 502 to have a margin of error of 0.03 in approximation of proportion of people who would black out at 6 or more Gs.

3 0

3 years ago