Answer:
As given, measure of angle 4 is 70°
Then what would be the measure of ∠8.
Following cases comes into consideration
1. If ∠4 and ∠8 are supplementary angles i.e lie on same side of Transversal, then
∠4 + ∠8=180°
⇒70°+∠8=180° [∠4=70°]
⇒∠8=180°-70°
⇒∠8=110°
<u>2nd possibility</u>
But if these two angles i.e ∠4 and ∠8 forms a linear pair.Then
⇒ ∠4 + ∠8=180°
⇒70°+∠8=180° [∠4=70°]
⇒∠8=180°-70°
⇒∠8=110°
<u>3rd possibility</u>
If ∠4 and ∠8 are alternate exterior angles.
then, ∠4 = ∠8=70°
<u>4th possibility</u>
If If ∠4 and ∠8 are corresponding angles.
then, ∠4 = ∠8=70°
Out of four options given Option A[ 110° because ∠4 and ∠8 are supplementary angles], Option B[70° because ∠4 and ∠8 are alternate exterior angles.] and Option D[70° because ∠4 and ∠8 are corresponding angles.] are Correct.
The answer is -2.21428571429
This is a factorial sequence that can be modeled by An = n!. As you may see, the increasing numbers are factorials of 1,2,3,4, and 5. Factorial means multiplying backwards and is represented by !. For example, 1! is 1*1 =1. 2! is 2*1, 3! is 3*2*1, 4! is 4*3*2*1 etc.
Answer:
4
Step-by-step explanation:
Is that a log with the base of 3√(2) ?
If so....my calculator says the answer is 4
Let's see if we can do it w/ou the calculator:
3 sqrt(2)^x = 324 = 3^4 * 2^2 Now 'LOG' both sides:
x log (3 sqrt 2) = log (3^4 *2^2) = 4 log ( 3 * 2^(2/4)) = 4 log (3 sqrt2)
now divide both sides by log (3 sqrt2 )
x = 4 (If I did the math correctly ! )
Answer:
e^2 -7 = x
Step-by-step explanation:
2=ln(x+7)
Raise each side to the base of e
e^2 = e^ln (x+7)
The e^ln cancel
e^2 = x+7
Subtract 7 from each side
e^2 -7 = x +7-7
e^2 -7 = x
