Answer:
15/56
Step-by-step explanation:
5 people have a license
3 people don't
? = Probability that first person has a license and second does not
We can divide the problem into two sections, the first being the probability of the first person having a license, and the second section is the probability that the second person doesn't have a license.
P1 = Probability of the first person having a license, there are 5 out of 8 person having a license, thus P1 = 5/8.
P2 = Probability of the second person having a license. There are 3 people not having a license, out of 8-1 = 7 persons available, since one is taken already from the first choice, therefore P2 = 3/7.
P1 and P2 are dependent events, thus P(1,2) = P1 * P2.
P(1,2) = P1 * P1 = 5/8 * 3/7 = 15/56
Answer: (6 , 3)
Step-by-step explanation: Given
x + 3y =15 ------- equation 1
4x + 2y = 30 --------- equation 2
x = 15 - 3y
Put value of x in equation 2
4 (15 - 3y) + 2y = 30
60 - 12y + 2y = 30
-10y = -30
divide by '-10' on both sides
y = 3
now, put value of y in equation 1
x + 3(3) = 15
x + 9 = 15
x = 15 - 9
x = 6
So , (x , y) = (6 , 3)
-18.2 + 3.6= -14.6 is the answer to the question
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