The percentage of young adults send between 128 and 158 text messages per day is; 34%
<h3>How to find the percentage from z-score?</h3>
The distribution is approximately Normal, with a mean of 128 messages and a standard deviation of 30 messages.
We are given;
Sample mean; x' = 158
Population mean; μ = 128
standard deviation; σ = 30
We want to find the area under the curve from x = 248 to x = 158.
where x is the number of text messages sent per day.
To find P(158 < x < 248), we will convert the score x = 158 to its corresponding z score as;
z = (x - μ)/σ
z = (158 - 128)/30
z = 30/30
z = 1
This tells us that the score x = 158 is exactly one standard deviation above the mean μ = 128.
From online p-value from z-score calculator, we have;
P-value = 0.34134 = 34%
Approximately 34% of the the population sends between 128 and 158 text messages per day.
Read more about p-value from z-score at; brainly.com/question/25638875
#SPJ1
Answer: (A) linear decrease
Step-by-step explanation:
linear decrease is when something empties for the same rate.
Answer:
I answered it for u before :D
Answer:
46656 to the power 4
Step-by-step explanation:
6 to the power 6 = 6 × 6 × 6 × 6 × 6 × 6 = 46656
(46656) to the power 4 = 46656 × 46656 × 46656 × 46656
This answer is undefined, so we will leave it at 46656 to the power 4.
Answer:
n = 3
m = -1/2
Step-by-step explanation:
Multiply the second equation by 4
4(n - 2)x + y = 4(n + m) Y is now correct.
4(n - 2) = 4 Remove the brackets
4n - 8 = 4 Add 8 to both sides
4n = 8 + 4 Combine
4n = 12 Divide by 4
n = 3 x is now correct
4(n - 2) = 4
4(3 -2) = 4
4 = 4
Now you have to worry about m
4(n + m) = 10
n = 3
4(3 + m) = 10 Divide by 4
m + 3 = 10/4
m + 3 = 2.5 Subtract 3 from both sides.
m = 2.5 - 3
m = - 1/2
