A=(1,3,5.7,9) B= (2,4,6,8,10)C= (1,5,6,7,9)A intersects (B intersects C)=
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When you illustrate the problem, it would look like the diagram shown in the picture. There are pictures, each with a length of 6 inches, that are placed all around the perimeter. To solve the number of pictures, the solution is as follows:
Size of picture = 6 inches * 1 ft/12 inches = 0.5 ft/picture
Pictures along the length = 7 ft * 1 picture/0.5 ft = 14 pictures
Pictures along the width = 4 ft * 1 picture/0.5 ft = 8 pictures
Since perimeter is 2L + 2W, the total number of pictures is:
Total pictures = 2(14) + 2(8) = 44 pictures
Size of picture = 6 inches * 1 ft/12 inches = 0.5 ft/picture
Pictures along the length = 7 ft * 1 picture/0.5 ft = 14 pictures
Pictures along the width = 4 ft * 1 picture/0.5 ft = 8 pictures
Since perimeter is 2L + 2W, the total number of pictures is:
Total pictures = 2(14) + 2(8) = 44 pictures