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3 years ago

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On Monday the price for bottled water was 5 bottles for $12.20. On Saturday the price was 3 bottles for $7.65. Which day had the

higher unit price?

1 answer:

kolbaska11 [484]3 years ago

7 0

Answer:

Saturday

Step-by-step explanation:

Monday had a unit rate of $2.44 per bottle

Saturday had a unit rate of $2.55 per bottle.

I wonder...

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Read 2 more answers

Given a circle with centre O and radius 2.4cm. P is a point such that the lenght of the tengent from Q to the circle is 4.5cm. F

skelet666 [1.2K]

Answer:

5.1 cm

Step-by-step explanation:

(Probable) Question;

Given a circle with center <em>O</em> and radius 2.4 cm.<em> P</em> is a point on the tangent that touches the circle at point <em>Q</em>, such that the length of the tangent from <em>P </em>to <em>Q</em> is 4.5 cm. Find the length of OP

The given parameters are;

The radius of the circle with enter at <em>O</em>, $\overline{OQ}$ = 2.4 cm

The length of the tangent from<em> P</em> to the circle at point <em>Q, </em> $\overline{PQ}$ = 4.5 cm

The length of OP = Required

By Pythagoras's theorem, we have;

$\overline{OP}$ ² = $\overline{OQ}$ ² + $\overline{PQ}$ ²

∴ $\overline{OP}$ ² = 2.4² + 4.5² = 26.01

$\overline{OP}$ = √26.01 = 5.1

The length of OP = 5.1 cm

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2 years ago

Suppose T is the transformation from ℝ2 to ℝ2 that results from a reflection over the y-axis followed by a reflection over the x

LenKa [72]

<u>Answer:</u>

A = \begin{pmatrix}-1 & 0 \\0 & -1\end{pmatrix}

<u>Step-by-step explanation:</u>

Let, there be a point (x , y) in R2

After reflection on Y axis, it will be ( -x , y) and thereafter if we reflect the image over X -axis , it will be (-x , -y)

So,

we need to find out a matrix

[tex]\begin{pmatrix}a & b \\c & d\end{pmatrix}[tex]

such that,

(x , y) [tex]\begin{pmatrix}a & b \\c & d\end{pmatrix}[tex] = (-x. -y)

So, we have the following set of equations.

ax + cy = -x ------------(1)

bx + dy= -y-----------(2)

We can get the solution (by inspection) as,

[tex]\begin{pmatrix}a & b \\c & d\end{pmatrix}[tex]

= [tex]\begin{pmatrix}-1 & 0 \\0 & -1\end{pmatrix}[tex]

So, the matrix is,

A = \begin{pmatrix}-1 & 0 \\0 & -1\end{pmatrix} (answer)

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3 years ago