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n200080 [17]
3 years ago
6

3x+6 factored form please help asap.

Mathematics
1 answer:
sdas [7]3 years ago
6 0

Answer:

3(x+2)

Step-by-step explanation:

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HELPPPP!!! i’m confused
defon
What are you even doing
4 0
3 years ago
n oblong box has a volume equal to lwh, where l is the length, w is the width, and h is the height. If the volume is 24 cubic fe
Eddi Din [679]
For this case the volume of the box is given by:
 V = l * w * h
 Where,
 V = 24 feet ^ 3
 Substituting values we have:
 24 = l * w * h
 Clearing the value of h we have:
 h = 24 / (l * w)
 Answer:
 
The height in terms of the other sides is:
 
h = 24 / (l * w)
8 0
3 years ago
A=20<br> B=10<br> C=23<br> D=29.2
11111nata11111 [884]
It’s 20 inches I think
3 0
2 years ago
) the top and bottom margins of a poster are 4 cm and the side margins are each 5 cm. if the area of printed material on the pos
grin007 [14]
If x represents the width of the poster (including borders), the area of the finished poster can be written as
.. a = x*(390/(x -10) +8)
.. = 8x +390 +3900/(x -10)

Then the derivative with respect to x is
.. da/dx = 8 -3900/(x -10)^2
This is zero at the minimum area, where
.. x = √(3900/8) +10 ≈ 32.08 . . . . cm
The height is then
.. 390/(x -10) +8 = 8 +2√78 ≈ 25.66 . . . . cm

The poster with the smallest area is 32.08 cm wide by 25.66 cm tall.

_____
In these "border" problems, the smallest area will have the same overall dimension ratio that the borders have. Here, the poster is 10/8 = 1.25 times as wide as it is high.
8 0
3 years ago
A projectile is fired into the air with an initial vertical velocity of 160 ft/sec from ground level. How many seconds later doe
djverab [1.8K]

The maximum height of the projectile is the maximum point that can be gotten from the projectile equation

The projectile reaches the maximum height after 5 seconds

The function is given as:

\mathbf{h(t) = -16t^2 + 160t}

Differentiate the function with respect to t

\mathbf{h'(t) = -32t + 160}

Set to 0

\mathbf{h'(t) = -32t + 160 = 0}

So, we have:

\mathbf{-32t + 160 = 0}

Collect like terms

\mathbf{-32t =- 160 + 0}

\mathbf{-32t =- 160}

Solve for t

\mathbf{t = \frac{- 160}{-32}}

\mathbf{t = 5}

Hence, the projectile reaches the maximum after 5 seconds

Read more about maximum values at:

brainly.com/question/6636648

8 0
3 years ago
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