Answer:
In this case we use the Poisson distribution because we are talking about the occurrence of an event (number of tracks) over a specified interval (in this case an area interval).
The probability of the event occurring x times over an interval is:
P(x) = nˣ × e⁻ⁿ ÷ x!
where n is the mean.
a) P(7) = 6⁷ × e⁻⁶ ÷ 7! = 0.1376
b) P(x ≥ 3) = 1 - P(x < 3) = 1 - P(2) - P(1) - P(0)
P(2) = 6² × e⁻⁶ ÷ 2! = 0.0446
P(1) = 6¹ × e⁻⁶ ÷ 1! = 0.0149
P(0) = 6⁰ × e⁻⁶ ÷ 0! = 0.0025
P(x ≥ 3) = 0.9380
c) P(2 < x < 7) = P(3) + P(4) + P(5) + P(6) = 0.0892 + 0.1339 + 0.1606 + 0.1606 = 0.5443
d) The mean is going to be 6.
e) The standard deviation is √n = √6 = 2.4
( x -3 )² = y - 4
y = ( x - 3 )² + 4
One solution is located at the vertex: ( 3, 4 ).
y = - x + b
4 = - 3 + b
b = 7
( x - 3 )² = - x + 7 - 4
x² - 6 x + 9 = - x + 3
x² - 5 x + 6 = 0
x² - 2 x - 3 x + 6 = 0
x ( x - 2 ) - 3 ( x - 2 ) = 0
( x - 2 ) ( x - 3 ) = 0
x 1 = 2, x 2 = 3
y 1 = 5, y 2 = 4.
In order for this solution to be reasonable, the 2nd equation must be:
y = - x + 7
Answer:
x=15
Step-by-step explanation:
The answer is A
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