3 years ago

Y=-3/2x+15 ........................

Mathematics

1 answer:

lorasvet [3.4K]3 years ago

8 0

What is the question? This is just a function.

You might be interested in

When does the expression below equal

SIZIF [17.4K]

Answer: n(7)+3=10
Explanation: 7+3 equals 10

4 0

3 years ago

Find the slope of the line that contains the two points (0,1) and (1,3)

klio [65]

Answer:

m=2 or y=2x+1

Step-by-step explanation:

first use the y2-y1/x2-x1 formula and then use y=mx+b formula

plug in 3 for y2 and 1 for y1

plug in 1 for x2 and 0 for x1

$\frac{3-1}{1-0} =\frac{2}{1} =2$

so ur slope is 2

_______________

for y=mx+b *extra info ig if u need it just incase*

i usually use the first point for this but u can use any one u want

plug in 0 for x

plug in 1 for y

and plug in 2 for m

1=2(0)+b

2*0=0

1=0+b

subtract o on both sides

1=b and b is ur y-intercept

y=2x+1

hope this helps

7 0

3 years ago

Help needed right away this is timed

ss7ja [257]

I think it might be x

3 0

3 years ago

Which number line shows 2 + (-5)?

ladessa [460]

Answer:

-3

Step-by-step explanation:

2+(-5)

2-5=-3

that is you solve the equation and trace it on the number line

7 0

3 years ago

A small business assumes that the demand function for one of its new products can be modeled by p = Cekx. When p = $40, x = 1000

Maru [420]

Answer:

C= 82.1116

k=-0.0007192

Step-by-step explanation:

$p=Ce^{kx}\\40=Ce^{k1000}\\30=Ce^{k1400}\\$

Applying logarithmic properties yields in the following linear system:

$ln(40) = ln(C) + 1000k\\ln(30) = ln(C) + 1400k$

Solving for k:

$ln(40) = ln(C) + 1000k\\ln(30) = ln(C) + 1400k\\400 k = ln(30)-ln(40)\\k=-0.0007192$

Solving for C:

$40=Ce^{-0.0007192*1000}\\C= \frac{40}{e^{-0.0007192*1000}}\\C=82.1116$

C= 82.1116

k=-0.0007192

6 0

3 years ago