Answer:
D
Step-by-step explanation:
It's easiest to divide everything by 3.
Answer: The area is 572.5566
Step-by-step explanation:
27÷2=r=13.5
A=πr²
A=3.1416(π) · 13.5²(r)
A=572.5566
The sum of all the even integers between 99 and 301 is 20200
To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.
In this case, the first even integer will be 100 and the last even integer will be 300.
nth term of the AP = first term + (n-1) x common difference
⇒ 300 = 100 + (n-1) x 2
Therefore, n = (200 + 2 )/2 = 101
That is, there are 101 even integers between 99 and 301.
Sum of the 'n' terms in an AP = n/2 ( first term + last term)
= 101/2 (300+100)
= 20200
Thus sum of all the even integers between 99 and 301 = 20200
Learn more about arithmetic progressions at brainly.com/question/24592110
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Answer:
let's start with
6a<42
a<7
Next we simplify
a+4>7
a>7-4
a>3
Step-by-step explanation:
Answer
3<a<7
Answer:
The given sequence is:
a(2)=1
a(3)=3
a(4)=9
We are to find the average rate of change between n=3 and n=4 for the given function.
Average rate of change =
So the average rate of change for the given function from n = 3 to n = 4 is 6
Step-by-step explanation:
