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Wittaler [7]
2 years ago
14

Dos condiciones anormales en el hombre, que son las cataratas y la fragilidad de huesos son debidas a alelos dominantes. Un homb

re con cataratas y huesos normales cuyo padre tenía ojos normales, se casó con una mujer sin cataratas pero con huesos frágiles, cuyo padre tenía huesos normales. Calcula la probabilidad de: a) Tener un hijo completamente normal b) Que tenga cataratas y huesos normales c) Que tenga ojos normales y huesos frágiles d) Que padezca ambas enfermedades.
Biology
1 answer:
SpyIntel [72]2 years ago
7 0

Answer:

La probabilidad de:

a) Tener un hijo completamente normal, cchh = 25%

b) Que tenga cataratas y huesos normales C-hh = 25%

c) Que tenga ojos normales y huesos frágiles ccH- = 25%

d) Que padezca ambas enfermedades C-H- = 25%.

Explanation:

<u>Datos disponibles:</u>

  • Alelo dominante C expresa cataratas
  • Alelo recesivo c expresa visión normal
  • Alelo dominante H expresa fragilidad de huesos
  • Alelo recesivo h expresa huesos normales

Los posibles genotipos para cada característica entonces son:

  • CC y Cc ----> Cataratas
  • cc -------------> Ojos normales
  • HH y Hh ----> Huesos frágiles
  • hh--------------> Huesos normales

Sabiendo esto, podemos deducir los genotipos del hombre y la mujer involucrados en la cruza.

  • Hombre con cataratas y huesos normales, tiene genotipo C-hh
  • Padre del hombre tiene ojos normales, cc

El padre del hombre es homocigota recesivo, expresando ojos normales. Esto significa que solo pudo heredarle al hijo (el hombre) un alelo recesivo, c. Pero el hombre expresa cataratas, lo que significa que porta también un alelo dominante, probablemente heredado de la madre. Entonces el hombre es heterocigota para el tipo de ojos. Y puesto que tiene huesos normales, sabemos que es homocigota recesivo para esta característica.

Genotipo del Hombre: Cchh

  • Mujer sin cataratas  y huesos frágiles, tiene genotipo ccH-
  • Padre de la mujer con huesos normales, hh

El padre de la mujer tiene huesos normales, implicando que su genotipo es homocigota recesivo y que solo puede heredarle a la progenie alelos recesivos. La mujer tiene huesos frágiles, lo que supone que heredó el alelo dominante de su madre. Puesto que recibió un alelo dominante de la madre y uno recesivo del padre, la mujer es entonces heterocigota para la característica en cuestión. Ella también tiene visión normal, lo que significa que su genotipo para esta característica es homocigota recesivo.

Genotipo de la mujer: ccHh

Sabiendo los genotipos de ambos integrantes de la pareja, podemos realizar la cruza:

Cruza:         Hombre  x    Mujer

Parentales)  Cchh      x      ccHh

Gametas)  Ch, ch, Ch, ch  (hombre)

                 cH, ch, cH, ch  (mujer)

Cuadro de Punett)

                 Ch        ch         Ch        ch

     cH     CcHh   ccHh     CcHh    ccHh

     ch      Cchh    cchh     Cchh     cchh  

     cH     CcHh   ccHh     CcHh    ccHh

     ch      Cchh    cchh     Cchh     cchh  

F1) Genotipos y Fenotipos:

  •     4/16 = 1/4 = 25% CcHh, Cataratas y huesos frágiles
  •     4/16 = 1/4 = 25% ccHh, Ojos normales y huesos frágiles
  •     4/16 = 1/4 = 25% Cchh, Cataratas y huesos normales
  •     4/16 = 14 = 25% cchh, ojos normales y huesos normales

   

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