10 5/12 can be turned into a improper fraction by multiplying 10 and 12. You get 120. Then you can add 5 and get 125/12.
THE ANSWER IS 125/12!
Answer:
![P(x) = 190 x -x^2](https://tex.z-dn.net/?f=%20P%28x%29%20%3D%20190%20x%20-x%5E2%20)
In order to maximize the last equation we can derivate the function in term of x and we got:
![\frac{dP}{dx} = 190 -2x](https://tex.z-dn.net/?f=%20%5Cfrac%7BdP%7D%7Bdx%7D%20%3D%20190%20-2x)
And setting this derivate equal to 0 we got:
![\frac{dP}{dx} = 190 -2x=0](https://tex.z-dn.net/?f=%20%5Cfrac%7BdP%7D%7Bdx%7D%20%3D%20190%20-2x%3D0)
And solving for x we got:
![x = 95](https://tex.z-dn.net/?f=%20x%20%3D%2095)
And for this case the value that maximize the profit would be x =95 and the corresponding profit would be:
![P(x=95)= 95(190-95)= 95*95 = 9025](https://tex.z-dn.net/?f=P%28x%3D95%29%3D%2095%28190-95%29%3D%2095%2A95%20%3D%209025)
Step-by-step explanation:
For this case we have the following function for the profit:
![P(x) = x(190-x)](https://tex.z-dn.net/?f=%20P%28x%29%20%3D%20x%28190-x%29)
And we can rewrite this expression like this:
![P(x) = 190 x -x^2](https://tex.z-dn.net/?f=%20P%28x%29%20%3D%20190%20x%20-x%5E2%20)
In order to maximize the last equation we can derivate the function in term of x and we got:
![\frac{dP}{dx} = 190 -2x](https://tex.z-dn.net/?f=%20%5Cfrac%7BdP%7D%7Bdx%7D%20%3D%20190%20-2x)
And setting this derivate equal to 0 we got:
![\frac{dP}{dx} = 190 -2x=0](https://tex.z-dn.net/?f=%20%5Cfrac%7BdP%7D%7Bdx%7D%20%3D%20190%20-2x%3D0)
And solving for x we got:
![x = 95](https://tex.z-dn.net/?f=%20x%20%3D%2095)
And for this case the value that maximize the profit would be x =95 and the corresponding profit would be:
![P(x=95)= 95(190-95)= 95*95 = 9025](https://tex.z-dn.net/?f=P%28x%3D95%29%3D%2095%28190-95%29%3D%2095%2A95%20%3D%209025)
Step-by-step explanation:
Solution,
since two of these triangle are similar so,
i) LK/LJ=MN/NO
or,j/8=18/12
or,j=18×8/12
.°. j = 12m
ii)JK/JL=MO/NO
or,10/8=n/12
or,120/8=n
.°.n=15m
Sorry i cant answer with the cracks...can't see