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Black_prince [1.1K]
3 years ago
13

If 24= 2f+3f+f, find f​

Mathematics
2 answers:
kupik [55]3 years ago
4 0

\huge\textsf{Hey there!}

\textsf{24= 2f + 3f + f}\\\text{COMBINE the LIKE TERMS}\\\\\textsf{2f + 3f + f}\\\textsf{2f + 3f = \bf 5f}\\\textsf{5f + f}\\\textsf{= \bf 6f}\\\text{New equation: \textsf{6f = 24}}\\\text{DIVIDE 6 to BOTH SIDES}\\\mathsf{\dfrac{6f}{6}=\dfrac{24}{6}}\\\textsf{CANCEL out: }\mathsf{\dfrac{6}{6}}\textsf{ because that gives you 1}\\\textsf{KEEP: }\mathsf{\dfrac{24}{6}}\textsf{ because that helps solve for the f-value}\\\\\mathsf{\dfrac{24}{6}=\bf f}\\\\\\\mathsf{\dfrac{24}{6}=24\div6=\bf 4}

\boxed{\boxed{\large\textsf{Answer: \huge \bf f = 4}}}\huge\checkmark

~\large\textsf{Good luck on your assignment and your day!}

~\frak{Amphitrite1040:)}

VashaNatasha [74]3 years ago
3 0

Answer:

6f = 24

f = 4

Step-by-step explanation:

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Answer:

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Aquí tenemos que comprar el frasco que tiene el menor costo por volumen.

h_1 = Altura del frasco corto

h_2 = La altura del frasco alto es el doble que el del frasco corto. = 2h_1

d_1 = Diámetro del frasco corto

d_2 = El diámetro del frasco alto es la mitad del frasco corto = \dfrac{1}{2}d_1

El volumen de un cilindro es \pi \dfrac{d^2}{4}h

La razón de los volúmenes de los frascos es

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El costo del frasco corto por unidad de volumen es

\dfrac{8000}{V_1}=\dfrac{8000}{2V_2}=\dfrac{4000}{V_2}

El costo del frasco alto por unidad de volumen es

\dfrac{4500}{V_2}=\dfrac{4500}{V_2}

\dfrac{4000}{V_2}

Entonces, el costo del frasco corto por unidad de volumen es menor que el costo por unidad de volumen del frasco alto.

Por lo tanto, deberíamos tomar el frasco corto.

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