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Anvisha [2.4K]
3 years ago
9

shamillia sent 60 text messages. 15% of those messages were to her mother. how many text messages did shamillia send to her moth

er ?
Mathematics
1 answer:
ratelena [41]3 years ago
6 0

Answer:

9 messages

Step-by-step explanation:

I think shamillia send 9 messages to her mother.

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The answers are: a, c, d, e

Step-by-step explanation:

I hope this helps

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What is the scale factor from Figure A to Figure B?
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3

Step-by-step explanation:

Because you can see there was one cube length in figure A and there was 3 cubes length in figure B.

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Does anyone know the answer to this? Algebra 2
natulia [17]

Answer:

Step-by-step explanation:

Sinθ = \frac{\text{Opposite side}}{\text{Hypotenuse}}

If, sinθ = -\frac{1}{2} and π < θ < \frac{3\pi }{2}

Since, sinθ is negative, angle θ will be in IIIrd quadrant.

And the measure of angle θ will be (180° + 30°)

θ = 210°

It's necessary to remember that tangent and cotangent of angle θ in quadrant III are positive.

Therefore, cos(210°) = -\frac{\sqrt{3} }{2}

tan(210°) = \frac{1}{\sqrt{3} }

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sec(210°) = -\frac{2}{\sqrt{3} }

cot(210°) = √3

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3 years ago
A pool drains 5000 gallons of water over the course of 5 hours. How many gallons of water, on average, does the pool drain each
Dmitry [639]

Answer:

D. 1000 gallons per hour

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The following six independent length measurements were made (in feet) for a line: 736.352, 736.363, 736.375, 736.324, 736.358, a
horrorfan [7]

Answer:

Assuming population data

\sigma = \sqrt{0.000354}=0.0188

Assuming sample data

s = \sqrt{0.000425}=0.0206

Step-by-step explanation:

For this case we have the following data given:

736.352, 736.363, 736.375, 736.324, 736.358, and 736.383.

The first step in order to calculate the standard deviation is calculate the mean.

Assuming population data

\mu = \frac{\sum_{i=1}^6 X_i}{6}

The value for the mean would be:

\mu = \frac{736.352+736.363+736.375+736.324+736.358+736.383}{6}=736.359

And the population variance would be given by:

\sigma^2 = \frac{\sum_{i=1}^6 (x_i-\bar x)}{6}

And we got \sigma^2 =0.000354

And the deviation would be just the square root of the variance:

\sigma = \sqrt{0.000354}=0.0188

Assuming sample data

\bar X = \frac{\sum_{i=1}^6 X_i}{6}

The value for the mean would be:

\bar X = \frac{736.352+736.363+736.375+736.324+736.358+736.383}{6}=736.359

And the population variance would be given by:

s^2 = \frac{\sum_{i=1}^6 (x_i-\bar x)}{6-1}

And we got s^2 =0.000425

And the deviation would be just the square root of the variance:

s = \sqrt{0.000425}=0.0206

6 0
3 years ago
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