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Mariulka [41]
3 years ago
15

On a coordinate plane, point A is 7 units to the left. Point B is at (0, 0). Point C is 7 units to the right. Point D is 7 units

up .Point E is 7 units down.
Which point is located at (0, –7)?
Mathematics
2 answers:
Anastaziya [24]3 years ago
7 0

Answer:

Point E

Step-by-step explanation:

In (x,y) it represents horizontal, then vertical coordinates. So, if x is 0, that means it hasn't moved left or right. Since y is -7, that means it when down by 7 units from the origin.

Savatey [412]3 years ago
4 0

Answer:

point a

Step-by-step explanation:

(0,-7) would be left 7 units so its point a

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Answer:

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Step-by-step explanation:

From the information given:

BY applying sphere coordinates:

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The intersection that takes place in the sphere and the cone is:

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This implies that:

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V  = \int \limits^{\pi/2}_{\pi/4} \ sin \phi  \ d \phi  \int \limits ^{2\pi}_{0} d \theta \int \limits^9_0 \rho   ^2 d\rho

V = \bigg [-cos \phi  \bigg]^{\pi/2}_{\pi/4}  \bigg [\theta  \bigg]^{2 \pi}_{0} \bigg [\dfrac{\rho^3}{3}  \bigg ]^{9}_{0}

V = [ -0+ \dfrac{1}{\sqrt{2}}][2 \pi -0] [\dfrac{9^3}{3}- 0 ]

V = 243\sqrt{2} \ \pi

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