Answer:
See below.
Step-by-step explanation:
Given :-
x² + bx + c = 0 if x₁ + x₂ = -b and x₁x₂ = c
Solving :-
a) x₁ = 1/2 and x₂ = -3/4
=> x² + -(1/2 + -3/4)x + 1/2(-3/4)
=> x² + -(-1/4)x + (-3/8)
=> x² + 1/4x - 3/8
=> 8x² + 2x - 3 = 0
b) x₁ = 1 + √5 and x₂ = 1 - √5
=> x² + -(1 + √5 + 1 - √5)x + (1 + √5)(1 - √5)
=> x² - 2x + 1 - 5
=> x² - 2x - 4 = 0
Answer: 
Step-by-step explanation:
We can use the Rational Root Test.
Given a polynomial in the form:

Where:
- The coefficients are integers.
-
is the leading coeffcient (
)
-
is the constant term 
Every rational root of the polynomial is in the form:

For the case of the given polynomial:

We can observe that:
- Its constant term is 6, with factors 1, 2 and 3.
- Its leading coefficient is 2, with factors 1 and 2.
Then, by Rational Roots Test we get the possible rational roots of this polynomial:

25 because 5 times 5 is 25 im writing more because it has to be at least 20 characters
Step-by-step explanation:
190 long sleeve and 330 short sleeve
Answer:
7x -14=35 add 14 on both sides
7x= 49 then, divide 7 on the whole equation
<u>x=7</u>