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2 years ago

Evaluate the expression 3r^2 if r = 1/6.

Mathematics

2 answers:

mel-nik [20]2 years ago

6 0

Answer:

1/12

Step-by-step explanation:

This is the answer because:

1) 1/6^2 = 1/36

2) 1/36 x 3 = 3/36 = 1/12 ↔ 3 ÷ 3 = 1 & 36 ÷ 3 = 12 = 1/12

Therefore, the answer is 1/12.

Hope this helps! :D

Helen [10]2 years ago

4 0

Answer:

0.08333

Step-by-step explanation:

3(1/6)^2

1/6=0.1666

1/6^2=0.02777

3*0.02777=0.08333

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At the end of year X, automobile installment credit accounted for 36 percent of all outstanding consumer installment credit. At

murzikaleks [220]

Answer:

option (c) 475

Step-by-step explanation:

let the automobile installment credit be 'C'

Given:.

Automobile installment credit accounted for 36 percent of all outstanding consumer installment credit

Now,

57 billion is $\frac{1}{3}$ of automobile installment credit

57 billion = $\frac{1}{3}$ × C

C = 57 × 3

C = 171 billion

now,

installment credit accounted = 36% of all outstanding consumer installment credit

171 billion = 0.36 × all outstanding consumer installment credit

All outstanding consumer installment credit = $475 billion

Hence, the correct answer is option (c) 475

4 0

3 years ago

What is the value of x? <br> X=

brilliants [131]

Answer:

x=7

step-by-step explanation:

$\frac{5}{40} = \frac{3}{2x + 10}$

5(2x+10) =3×40

10x + 50 = 120

10x =120-50= 70

x = 70/10= 7

5 0

2 years ago

each interior angle of a regular polygon measures (10x+10) and each exterior angle measures(3x-12) how many sides does the polyg

katrin2010 [14]

Interior angle+exterior angle=180
10x +10 +3x -12 =180
13x-2=180
13X+182
X=14 sides

5 0

3 years ago

tony invests some money in a bank which pays 4% compound interest per year. he wants it to be worth over 6000 at the end of 3 ye

Sliva [168]

Tong is very very cool. He has so so much money he is so cool and he is extremely swag.

5 0

2 years ago

The restrictions on the variable in the division x+5/x+2 divided by x-3/x+1 are

oksian1 [2.3K]

Answer:

$x \neq-2 \text { and } x \neq-1$

Step-by-step explanation:

The restricted value is a value that makes the denominator of a function equal to zero. Thus, solving these function results in an undefined solution.

Thus, $x \neq-2$ and $x \neq-1$ are the restricted values for $\frac{x+5}{x+2}$ divided by $\frac{x-3}{x+1}$

Because, substituting $x=-2$ in $\frac{x+5}{x+2}$

Now, substituting $x=-2$ , we get,

$\begin{aligned}\frac{x+5}{x+2} &=\frac{x+5}{-2+2} \\&=\frac{x+5}{0}\end{aligned}$

Thus, results the solution undefined.

Also, substituting $x=-1$ in $\frac{x-3}{x+1}$

$\begin{aligned}\frac{x-3}{x+1} &=\frac{x-3}{-1+1} \\&=\frac{x-3}{0}\end{aligned}$

Thus results the solution undefined.

Hence, the restricted values are $x \neq-2 \text { and } x \neq-1$

7 0

2 years ago