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3 years ago

Helpppp in 8 asap plzz

Mathematics

1 answer:

Kisachek [45]3 years ago

6 0

On each shelf he has 9

His aunt gave him three, just put one book on the each shelf

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A stone is a British unit of weight equivalent to 14 pounds. After losing 1 1/2 stone. Jim is now 85% of his original weight. Wh

evablogger [386]

Answer:

Jim's current weight = 119 pounds

Step-by-step explanation:

1 Stone = 14 pounds

$1\frac{1}{2}$ stone = 1.5 stone

1.5 stone = 1.5 (14 pounds) = 21 pounds

Jim lost 21 pounds

Let X be Jim's Original Weight

Y be his present weight

As per given statement in the Question:

After losing 1.5 stones (21 pounds of weight) Jim now weighs Y

Present weight = original weight - 21

Y = X -21 Equation 1

Also Current Weight = 85 % (Original weight)

Y = 85 % (X) = $\frac{85X}{100}$

Y= $\frac{85X}{100}$

put in Equation 1

$\frac{85X}{100}$ = X-21

85X = (X-21) 100

85 X = 100 X -2100

2100 = 100 X - 85X

2100 = 15X

15 X = 2100

$X=\frac{2100}{15}$

X= 140 pounds ( Original Weight)

Current Weight = Y = Original weight - 21 (From Equation 1)

Y = X -21

Y = 140 -21

Y = 119 pounds (Current Weight)

5 0

2 years ago

Graph Y=3/4x - 1/2 Pleaseeeee help!!

Nimfa-mama [501]

I’m not 100% sure kind of a guess but I would x=2/3. Good luck

6 0

2 years ago

Read 2 more answers

Solving separable differential equation DY over DX equals xy+3x-y-3/xy-2x+4y-8

Ivanshal [37]

It looks like the differential equation is

$\dfrac{dy}{dx} = \dfrac{xy + 3x - y - 3}{xy - 2x + 4y - 8}$

Factorize the right side by grouping.

$xy + 3x - y - 3 = x (y + 3) - (y + 3) = (x - 1) (y + 3)$

$xy - 2x + 4y - 8 = x (y - 2) + 4 (y - 2) = (x + 4) (y - 2)$

Now we can separate variables as

$\dfrac{dy}{dx} = \dfrac{(x-1)(y+3)}{(x+4)(y-2)} \implies \dfrac{y-2}{y+3} \, dy = \dfrac{x-1}{x+4} \, dx$

Integrate both sides.

$\displaystyle \int \frac{y-2}{y+3} \, dy = \int \frac{x-1}{x+4} \, dx$

$\displaystyle \int \left(1 - \frac5{y+3}\right) \, dy = \int \left(1 - \frac5{x + 4}\right) \, dx$

$\implies \boxed{y - 5 \ln|y + 3| = x - 5 \ln|x + 4| + C}$

You could go on to solve for $y$ explicitly as a function of $x$ , but that involves a special function called the "product logarithm" or "Lambert W" function, which is probably beyond your scope.

8 0

1 year ago

Should the object be measured in grams or in kilograms?

Mashcka [7]

Feather: grams
bulldog:kilo
tv: kilo
penny: grams

6 0

3 years ago

Read 2 more answers

estimate the number of people who feel they are most productive outside normal office hours. the graph represents a survey of 13

enot [183]

I would say about 300 people

5 0

3 years ago