Answer:
Jim's current weight = 119 pounds
Step-by-step explanation:
1 Stone = 14 pounds
stone = 1.5 stone
1.5 stone = 1.5 (14 pounds) = 21 pounds
Jim lost 21 pounds
Let X be Jim's Original Weight
Y be his present weight
As per given statement in the Question:
After losing 1.5 stones (21 pounds of weight) Jim now weighs Y
Present weight = original weight - 21
Y = X -21 <u> Equation 1</u>
Also Current Weight = 85 % (Original weight)
Y = 85 % (X) =
Y=
put in Equation 1
= X-21
85X = (X-21) 100
85 X = 100 X -2100
or
2100 = 100 X - 85X
2100 = 15X
or
15 X = 2100

X= 140 pounds ( Original Weight)
Current Weight = Y = Original weight - 21 <u><em>(From Equation 1)</em></u>
Y = X -21
Y = 140 -21
Y = 119 pounds (Current Weight)
I’m not 100% sure kind of a guess but I would x=2/3. Good luck
It looks like the differential equation is

Factorize the right side by grouping.


Now we can separate variables as

Integrate both sides.



You could go on to solve for
explicitly as a function of
, but that involves a special function called the "product logarithm" or "Lambert W" function, which is probably beyond your scope.
Feather: grams
bulldog:kilo
tv: kilo
penny: grams