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OleMash [197]
3 years ago
8

Hi! Could you help me me out and solve these two problems? "eight less than the product of seven and xxx", and "the sum of six a

nd the product of three and d". Thank you!
Mathematics
1 answer:
Ann [662]3 years ago
3 0

Given:

The given statement are:

a. Eight less than the product of seven and x.

b. The sum of six and the product of three and d.

To find:

The expression for the given statements.

Solution:

a.

Product of 7 and x is 7×x = 7x.

Eight less than the product of seven and x is 7x - 8.

Therefore, the required expression for the statement "Eight less than the product of seven and x" is 7x-8.

b.

Product of 3 and d is 3×d = 3d.

The sum of six and the product of three and d is 6+3d.

Therefore, the required expression for the statement "The sum of six and the product of three and d" is 6+3d.

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Wendy scores 24 points in a basketball game. If all of her baskets were 3-point shots, how many baskets did she make?
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Step-by-step explanation:

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S+R+T=180

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An example of consecutive odd integers is 23, 25, 27, and 29. Find four consecutive odd integers with a sum of 160. Show your wo
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Step1: Define an odd integer.
Define the first odd integer as (2n + 1), for n = 0,1,2, ...,
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Step 2: Create four consecutive odd integers.
Multiplying n by 2 guarantees that 2n will be zero or an even number.
Therefore (2n + 1) is guaranteed to be an odd number.
By adding 2 to the odd integer (2n+1), the next number (2n+3) will also be an odd integer.

Let the four consecutive odd integers be
2n+1, 2n +3, 2n +5, 2n +7 

Step 3: require that the four consecutive integers sum to 160.
Because the sum of the four consecutive odd integers is 160, therefore
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n = 18

Because 2n = 36, the four consecutive odd integers are 37, 39, 41, 43.

Answer: 37,39,41,43

8 0
3 years ago
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