In the given figure, there are two right angled triangles.
Area of triangle = 1/2 × b × h
Area of shaded region = area of larger triangle - area of smaller triangle
= 1/2 × 15 × 18 - 1/2 × 8 × 9
= 135 - 36
= 99 ft^2
Thus, area of shaded region is 99 ft^2.
Remark
There is no short way to do this problem and no obvious way to get the answer other that to solve each part.
Solve
A
Multiply by 2
x + 1.6 = 2(x + 0.1) Remove the brackets
x + 1.6 = 2x + 0.1*2
x + 1.6 = 2x + 0.2 Subtract x from both sides
1.6 = x + 0.2 Subtract 0.2 from both sides
1.6 - 0.2 = x
1.4 = x
Circle A
B
Subtract 2x from both sides.
3x - 2x = 1.4
Circle B
C
Remove the brackets.
4x + 6 = 2x - 6 Add 6 to both sides
4x + 12 = 2x Subtract 4x from both sides.
12 = -2x Divide by - 2
12/-2 = x
x = - 6 Don't circle C
D
I'm going to be very scant in my solution of this. You can fill in the steps.
3x = 4.2
x = 4.2/3
x = 1.4
Circle D
Area of the circle can be calculated using the following rule:
area = pi*(radius)^2
For the first circle:
We are given that:
area = 1040.9 square units ....> I
For the second circle:
We are given that:
radius = 27 units
Therefore:
area = pi * (27)^2 = 2290.221044 square units ....> II
For the third circle:
We are given that:
circumference = 87.92 units
Therefore:
circumference = 2*pi*radius = 87.92
radius = 13.99 units
area = pi*(13.99)^2 = 615.12799 square units ...> III
For the fourth circle:
We are given that:
diameter = 19 units
Therefore:
radius = 19/2 = 9.5 units
area = pi*(9.5)^2 = 283.528 square units ....> IV
Based on the above, the order according to increasing area would be:
IV , III , I , II
hope this helps :)
In logarithm, inverse operations are applied.
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