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2 years ago

15

Which fraction is equivalent to the fraction shown by this model. 12/9

1 answer:

svp [43]2 years ago

5 0

Answer:

4/3

Step-by-step explanation:

12/9 is equivalent to 4/3, because you can divide both the numerator and denominator by the common factor of 3 and that will give you the correct fraction: 4/3.

Hope this helped.

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I need help pls and thx

Assoli18 [71]

Answer:

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Step-by-step explanation:

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2 years ago

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what number must be added to 3 and 8 so that the ratio of the first number to the second number is equal to 3 :4

Grace [21]

The answer is 12.
Steps
If that number is x
(3+x)/(8+x)=3/4
"Cross multply"
4(3+x)=3(8+x)
12+4x=24+3x
x=12
To check: add 12 to 3 and 8. 3+12=15 and 8+12=20. 15/20=3/4

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2 years ago

Greater 3/5 or .5625

labwork [276]

Answer: 3/5

Step-by-step explanation: 3/5 is equal to .6 so if is greater than .5625

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2 years ago

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HELP PLEASE WILL MARL BRANIEST IF right

Kaylis [27]

Answer:

A bit of a doosy, but bare with me: f*g*h(x) = $x^2+54x-12x\sqrt{x} -108\sqrt{x} +90$

Step-by-step explanation:

So explaining this is a bit awkward as well, but I can try...So

Starting from g(x) working that backwards into f(x), so...

g(x) = $x-3$

f(x) = $(x^4+9)$

Take your g(x) and plug it into your f(x) into every x you see

f(g(x)) = $(x-3)^4+9$ ~ I hope you can visualize this, but do you see how g(x) plugs into f(x)...

Now you still have one more step which you still need to include h(x), so

Remember h(x) = $\sqrt{x}$

Now plug in your h(x) into every x you see from f(g(x)) and it should look like...

$(\sqrt{x} -3)^4 + 9$

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2 years ago

1)The pyramid has a square base that us inscribed in the circular base of the cone. Draw an image of the composite shape of the

DENIUS [597]

Answer:

Diameter of the circle is $8\sqrt{2}$ units

Step-by-step explanation:

It is given that the vertices of the square fall on the circle.

So, the diagonal of the square is the diameter of the circle.

Also, the diagonal and the two sides of the square form a right angled triangle.

By Pythogoras theorem,

$hypotenuse^{2} =side^{2} +side^{2}$

= $8^{2} +8^{2}$

= $2(8^{2} )$

$hypotenuse=8\sqrt{2}$ units

Hence, the diameter of the circle is $8\sqrt{2}$ units

7 0

3 years ago