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3 years ago

2. An apartment complex has a demand given by p

Mathematics

1 answer:

zhuklara [117]3 years ago

6 0

Memes lamps in my I’m so sry

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A publisher requires 2⁄3 of a page of advertisements for every 5 pages in a magazine. If a magazine has 98 pages, to the nearest

rjkz [21]

Let x be the number of pages of advertisements.

Write a proportion from the table:

$\dfrac{2}{3}$ of a page of advertisment - 5 pages in a magazine

x pages of advertisment - 98 pages in a magazine,

then

$\dfrac{\dfrac{2}{3}}{x}=\dfrac{5}{98}.$

Find x:

$x=\dfrac{\dfrac{2}{3}\cdot 98}{5}=\dfrac{196}{15}=13\dfrac{1}{13}.$

Answer: 13 whole pages and $\dfrac{1}{13}$ of 14th page are advertisments, so 14 pages contain advertisments.

3 0

3 years ago

Please help geometry

maxonik [38]

Answer:

(1,2)

Step-by-step explanation:

5 0

2 years ago

I need help on this it’s about trig identities

Cerrena [4.2K]

Answer:

The answer to your question is:

Step-by-step explanation:

1.-

$\frac{1 + sin\alpha }{cos\alpha } + \frac{cos\alpha }{1 + sin\alpha } = 2 sec\alpha$

$\frac{(1 + sin\alpha)^{2} + cos^{2} \alpha }{cos\alpha (1 + sin\alpha) }$

$\frac{1 + 2sin\alpha + sin^{2} \alpha+ cos^{2} \alpha }{cos\alpha + sin\alphacos\alpha }$

$\frac{2 + 2sin\alpha }{cos\alpha+ sin\alpha cos\alpha }$

$\frac{2(1 + sin\alpha) }{cos\alpha(1 + sin\alpha ) }$

$\frac{2}{cos\alpha }$

2sec $\alpha$

2.-

sec²x - tanxsecx

$\frac{1}{cos^{2}x } - \frac{sinx}{cosx} \frac{1}{cosx}$

$\frac{1}{cos^{2} x} - \frac{sinx}{cos^{2}x}$

$\frac{1 - sinx}{cos^{2}x }$

$\frac{1 - sinx}{1 - sin^{2}x }$

$\frac{1 - sinx}{(1 - sinx)(1 + sinx)}$

$\frac{1}{1 + sinx}$

3 0

2 years ago

#1,2,2,3,5,6,7 I need work shown also please help

laiz [17]

I’m not sure about the estimates but the overall answers should be correct

4 0

3 years ago

The number of books sold over the course of the four-day book fair were 190, 100, 272, and 74. Assume that samples of size 2 are

g100num [7]

Answer:

the answer is below

Step-by-step explanation:

We have the total number of possible samples = 4 * 4 = 16 (As 4 choices for each value)

in addition we have to as all sample occur with equal probability, probability of each sample = 1/16, below is samling distribution of mean

x1 x2 probabilityP(x1,x2) sample mean

190 190 1/16 190

190 100 1/16 145

190 272 1/16 231

190 74 1/16 132

100 190 1/16 145

100 100 1/16 100

100 272 1/16 186

100 74 1/16 87

272 190 1/16 231

272 100 1/16 186

272 272 1/16 272

272 74 1/16 173

74 190 1/16 132

74 100 1/16 87

74 272 1/16 173

74 74 1/16 74

Summarizing above with adding duplicate values

sample mean probability

74 1/16

87 1/8

100 1/16

132 1/8

145 1/8

173 1/8

186 1/8

190 1/16

231 1/8

272 1/16

5 0

3 years ago