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Zolol [24]
3 years ago
13

When Riley goes bowling, her scores are normally distributed with a mean of 160 and

Mathematics
1 answer:
e-lub [12.9K]3 years ago
6 0

Answer:

The interval that would represent the middle 68% of the scores of all the games that Riley bowls is (147, 173).

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean of 160, standard deviation of 13.

Middle 68% of the scores of all the games that Riley bowls.

Within 1 standard deviation of the mean, so:

160 - 13 = 147.

160 + 13 = 173.

The interval that would represent the middle 68% of the scores of all the games that Riley bowls is (147, 173).

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True or False. Fred trades 2 tomatoes to Barney in exchange for 1 pumpkin. Fred and Barney both gain from the exchange. We can c
BabaBlast [244]

Answer:

False

Step-by-step explanation:

Both do not gain from the exchange. If producing 1 pumpkin is greater than 2 tomatoes, this means that Barney traded for less than he gave out in cost to produce 1 pumpkin. Barney should be demanding more tomatoes to make up the cost of producing 1 pumpkin. Fred makes a gain from the transaction. The selling price of tomatoes are less than a pumpkin. He can therefore sell 1 pumpkin to produce more than 2 tomatoes per pumpkin.

4 0
3 years ago
Find the value of the missing coefficient in the factored form of 8f^3-216g^3
adoni [48]

Answer:

The value of the missing coefficient is 12

Step-by-step explanation:

* Lets explain how to factorize the difference of two cubes

- The factorization of the difference of two cubes like a³ - b³, is a

  product of a binomial and trinomial

- The binomial is the cube root of the first term and the second term

∵ The ∛a³ = a and ∛b³ = b

∴ The binomial is (a - b)

- We will find the trinomial from the binomial by square the 1st term

 of the binomial and multiply the 1st term and the 2nd term of the

 binomial with opposite sign of the binomial and square the 2nd

 term of the binomial

∴ The trinomial is (a² + ab + b²

∴ The factorization of (a³ - b³) is (a - b)(a² + ab + b²)

* Lets solve the problem

∵ 8f³ - 216g³ is the difference of two cubes

∵ ∛(8f³) = 2f

∵ ∛(216g³) = 6g

∴ The binomial is (2f - 6g)

- Lets make the trinomial

∵ (2f)² = 4f²

∵ (2f)(6g) = 12fg

∵ (6g)² = 36g²

∴ The trinomial = (4f² + 12fg + 36g²)

∴ The factorization of 8f³ - 216g³ = (2f - 6g)(4f² + 12fg + 36g²)

∴ The value of the missing coefficient is 12

7 0
3 years ago
HELP ME PLEASE <br> True or false: z=−5 is a solution to the inequality −2|z−3|&lt;−20.
Dovator [93]

<em><u>your </u></em><em><u>question</u></em><em><u>:</u></em><em><u> </u></em>

<em>True or false: z=−5 is a solution to the inequality −2|z−3|<−20.</em>

<em><u>answer:</u></em><em><u> </u></em>

<em>-</em><em>2</em><em>|</em><em>z-3|</em><em><</em><em>-</em><em>2</em><em>0</em>

<em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>. </em><em> </em><em> </em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em>

<em> </em><em> </em><em> </em><em>-</em><em>2</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>-</em><em>2</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>|</em><em>z-3|</em><em><</em><em>1</em><em>0</em><em> </em>

<em>equation </em><em>1</em><em>:</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>equation </em><em>2</em><em>:</em><em> </em>

<em>z-3<</em><em>1</em><em>0</em><em>. </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>z-3></em><em>-</em><em>1</em><em>0</em><em> </em>

z<13 z>-13

<em>So </em><em>false, </em><em>z=</em><em>-</em><em>5</em><em> </em><em>is </em><em>not </em><em>a </em><em>solution </em><em>to the </em><em>inequality</em><em>.</em>

<em>hope </em><em>this </em><em>helps, </em><em>have </em><em>a </em><em>great </em><em>day! </em><em>:</em><em>)</em>

7 0
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Schach [20]
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Because you're not studying!

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Answer step-by-step explanation:

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