All categories

3 years ago

ASAP!!! Which of these graphs could represent an exponential relation (Explain)

Mathematics

1 answer:

Margarita [4]3 years ago

6 0

Answer:

B. looks like the best answer that fits this question.

If i'm wrong then my fault.

Step-by-step explanation:

When looking at choice (B) you can see it started at a decreasing point but slowly growing. Exponential relations are images or equations that describe growth and they always have the same function. If you look at the other choices you see that they either increase but then decrease or they don't match the formula for (exponential relations).

That's as good as I can do I dont knw if this what ur teacher is looking for but I tried :/

You might be interested in

The tangents to the curve with equation y = x^3-3x at the points A and B with x coordinates −1 and 4 respectively meet at the po

sladkih [1.3K]

Answer:

$\displaystyle C=\left(\frac{26}{9}, 2\right)$

Step-by-step explanation:

We need to find the equation of the tangent lines of Points A and B.

Differentiate the equation:

$\displaystyle \frac{dy}{dx}=3x^2-3$

Point A has an x-coordinate of -1. Hence, the slope of its tangent line is:

$\displaystyle \frac{dy}{dx}\Big|_{x=-1}=3(-1)^2-3=0$

Find the y-coordinate of Point A using the original equation:

$y(-1)=(-1)^3-3(-1)=2$

Hence, Point A is (-1, 2).

Thus, the tangent line at Point A is:

$y-2=0(x-(-1))$

Simplify:

$y=2$

Point B has an x-coordinate of 4. Hence, the slope of its tangent line is:

$\displaystyle \frac{dy}{dx}\Big|_{x=4}=3(4)^2-3=45$

Find the y-coordinate of Point B:

$y(4)=(4)^3-3(4)=52$

Thus, Point B is at (4, 52).

So, the tangent line at Point B is:

$y-52=45(x-4)$

Simplify:

$y=45x-128$

Point C occurs at the intersections of the tangent lines of Points A and B. Set the two equations equal to each other and solve for x:

$2=45x-128$

We acquire:

$\displaystyle x=\frac{26}{9}$

Since one of our equations is y = 2, the y-coordinate is 2.

Hence, Point C is:

$\displaystyle C=\left(\frac{26}{9}, 2\right)$

5 0

3 years ago

Read 2 more answers

Find the work done in winding up a 175 ft cable that weighs 3 lb/ft.

nignag [31]

Answer:

$work \ done= 45937.5$

Step-by-step explanation:

Work done is given by

$work \ done=\int_a^b w(d-x) \ dx$ , where d = length of cable and w = weight of cable.

Here, d = 175 ft and w = 3 lb/ft

Now, $work \ done=\int_0^{175} 3(175-x) \ dx$

$work \ done= 3\left [175x-\frac{x^2}{2} \right ]_0^{175}$

$work \ done= 3\left [175^2-\frac{175^2}{2} \right ]$

$work \ done= 3\cdot \frac{175^2}{2}$

$work \ done= 45937.5$

8 0

3 years ago

Yumi and Juan pick up litter along the highway at the same rate. Yumi picks up litter for 3 miles and takes 2 hours longer than

Kay [80]

Answer:

How long did Yumi spend picking up litter?

6 HOURS!!!!

Step-by-step explanation:

just took it on ed:)

5 0

3 years ago

Read 2 more answers

Can someone please calculate the length ?

masya89 [10]

<h3>Answer: 11/20</h3>

=====================================================

Work Shown:

x = unknown horizontal length

1/5 = 0.2

Perimeter = 2*(width + length)

P = 2*(0.2 + x)

P = 0.4 + 2x

Set this equal to the given perimeter of 1 & 1/2 = 1.5 and solve for x

0.4 + 2x = 1.5

2x = 1.5-0.4

2x = 1.1

x = (1.1)/2

x = 0.55

x = 55/100

x = (5*11)/(5*20)

x = 11/20

5 0

3 years ago

Due tomorrow !!! Ugh

Y_Kistochka [10]

1.) 2
2.) 5
3.)84
4.) 4
5.) 31
6.).5

7 0

3 years ago