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Finger [1]
3 years ago
7

What is the equation of the line in point slope form

Mathematics
1 answer:
Phoenix [80]3 years ago
5 0
Well... to solve use rise over run... that is to find the slope,
now to find the y-intercept you look at what coordinate crosses the y-axis. 
y= (what you got for the slope Ex. 1/2)x + (the y-intercept)

Figure it out and you got the answer with just a bit of help!!!

Hope this helps!
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Alex drew the triangles shown. What correctly describes the triangles
KATRIN_1 [288]

Answer:

Congruent triangles

Step-by-step explanation:

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3 years ago
What is the median of the following numbers
den301095 [7]

Answer: You did not give me any numbers...

Step-by-step explanation:

just to say, The median is the value separating the higher half of a data sample, a population, or a probability distribution, from the lower half. In simple terms, it may be thought of as the "middle" value of a data set.

3 0
3 years ago
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For a given input value b, the function f outputs a value a to satisfy the following equation. 4a+7b=−52 Write a formula for ) f
Sergio [31]

Answer: Our required formula becomes :

a=f(b)=-13-\frac{7}{4}b

Step-by-step explanation:

Since we have given that

4a+7b=-52\\

We need to write a formula for f(b) in terms of b So, it becomes

4a=-52-7b\\\\a=\frac{-52-7b}{4}\\\\a=\frac{-52}{4}-\frac{7b}{4}\\\\a=-13-\frac{7b}{4}

Hence, our required formula becomes :

a=f(b)=-13-\frac{7}{4}b


5 0
3 years ago
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When a graph of a cubic polynomial function rises to the left, it falls to the right true or false
serious [3.7K]
That would be true i think
6 0
3 years ago
A piece of cardboard is 13 inches by 26 inches. A square is to be cut from each corner and the sides folded up to make an open-t
Vanyuwa [196]

Answer:

Hence the maximum possible volume will be the 778.53 c.c

Step-by-step explanation:

Given:

A rectangle with 13 x 26 dimensions

And corners are cut to form side squares.

To Find:

Maximum possible volume for box

Solution :

Consider a rectangle of 13 x 26 dimension with and side of square  at corner be x.

(Refer the attachment)

Now,

Formulating the volume equation for the box

So corner square sides we are going to fold up which makes height of the box

and remaining part will be length and breadth

As shown in fig,

Length=26-x

breadth=13-x

And height will be x

V(x)=x*(26-x)*(13-x)

To get maximum volume differentiate the above equation,

V(x)=x*(26*13-26*x-13*x+x^2)

V(x)=x^3-39x^2+338x\\

V'(x)=3x^2-78x+338

V''(x)=6x-78

Now ,Solve the Quadratic Equation to get x values,

3x^2-78x+338=0

x=[-b±(b^2-4ac)^1/2]/2a

x=[78±Sqrt[(78)^2-4*338*3)]/2*3

x=[78±Sqrt(3028)]/6

x=[78±55.027]/6

x=78+55.027/6 or x=78-55.027/6

x=22.17  or x=3.8288

Use these values in 6x-78 to know which value posses the max and min value for the function.

So when x=22.17

6x-78=6*22.17-78

=55.02>0  i.e function will have minimum value .

When x=3.8288

6*3.8288-78

=-55.0272<0 i.e. Function will have maximum value

Now, the function will defines the maximum volume

V(x)=x^3-39x^2+338x

V(x)=3.8288^3-39*(3.82883)^2+338*3.8288

V(x)=56.13-571.73+1294.13

V(x)=778.53 C.C

6 0
3 years ago
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