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Svetradugi [14.3K]

3 years ago

8

Chuck is picking up pecans in his yard. He discovered that 2 out of every 15 pecans are bad. If he picks up 840 pecans, about ho

w many will be bad in the group?

1 answer:

likoan [24]3 years ago

5 0

Answer:

Who picks up that many pecans?

Step-by-step explanation:

i get bored after like 30. jeez.

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With one toss of a single number cube, what is the probability of rolling a number less than three

guajiro [1.7K]

Assuming the number cube has six sides, there are only two numbers less than three so 2/6ths or (simplied) 1/3.

5 0

3 years ago

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Evaluate the permutation P(36,19)=____

kondaur [170]

Easy

nPr= $\frac{n!}{(n-r)!}$
here
36P19= $\frac{36!}{(36-19)!}=$
$\frac{36!}{(17)!}=$
$\frac{36*35*34*33*32*31*30*29*28*27*26*25*24*23*22*21*20*19*18}{1}=$
1045843337171591729971200000

6 0

4 years ago

Plz help ive been stuck on this one also !!

svetlana [45]

A)0.9, b) 0.6, c) 0.75, d)0.25

8 0

3 years ago

P1= (5,-4); p2=(8,-3);p3=(7,-10) find the length of each side of the triangle determined by three points

Dima020 [189]

so the points are, from P1 to P2, namely P1P2, and from P2 to P3, namely P2P3, and from P3 back to P1, namely P3P1.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ P1(\stackrel{x_1}{5}~,~\stackrel{y_1}{-4})\qquad P2(\stackrel{x_2}{8}~,~\stackrel{y_2}{-3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ P1P2=\sqrt{[8-5]^2+[-3-(-4)]^2}\implies P1P2=\sqrt{(8-5)^2+(-3+4)^2} \\\\\\ P1P2=\sqrt{3^2+1^2}\implies \boxed{P1P2=\sqrt{10}}\\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ P2(\stackrel{x_2}{8}~,~\stackrel{y_2}{-3})\qquad P3(\stackrel{x_2}{7}~,~\stackrel{y_2}{-10}) \\\\\\ P2P3=\sqrt{[7-8]^2+[-10-(-3)]^2}\implies P2P3=\sqrt{(7-8)^2+(-10+3)^2} \\\\\\ P2P3=\sqrt{(-1)^2+(-7)^2}\implies P2P3=\sqrt{50}\implies \boxed{P2P3=5\sqrt{2}}\\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ P3(\stackrel{x_2}{7}~,~\stackrel{y_2}{-10})\qquad P1(\stackrel{x_1}{5}~,~\stackrel{y_1}{-4}) \\\\\\ P3P1=\sqrt{[5-7]^2+[-4-(-10)]^2}\implies P3P1=\sqrt{(5-7)^2+(-4+10)^2} \\\\\\ P3P1=\sqrt{(-2)^2+6^2}\implies P3P1=\sqrt{40}\implies \boxed{P3P1=2\sqrt{10}}$

5 0

3 years ago

A bag contain 6 red and 5 green identical balls.

Ann [662]

Answer:

3/11 for two red balls

2/11 for two green balls

Step-by-step explanation:

6 red and 5 green balls

first ball - red= 6/11, green= 5/11

second red ball- 5/10=1/2, second green ball- 4/10= 2/5

Two red balls = 6/11*1/2= 3/11

Two green balls= 5/11*2/5= 2/11

8 0

3 years ago

Read 2 more answers