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Leno4ka [110]
3 years ago
6

The box-and-whisker plot below shows the age distribution of people at a family reunion. A box-and-whisker plot is shown. The nu

mber line goes from 8 to 72 in increments of 8. The whiskers range from 8 to 71, and the box ranges from 23 to 47. A line divides the box at 38. The stem-and-leaf plot below shows the same data. A stem and leaf plot is shown. The stems from top to bottom are 0, 1, 2, 3, 4, 5, 6, 7. The first column of leaves is 8, 0, 3, 1, 0, 0, 0. The second column of leaves is 9, 1, 3, 6, 1, 2, 1. The third column of leaves is blank, 4, 5, 6, 2, 3, blank. The fourth column of leaves is blank, 5, 6, 8, 4, 6, blank. The fifth column of leaves is blank, blank, 6, 9, 6, blank, blank. The sixth column of leaves is blank, blank, blank, 9, blank, blank, blank. The seventh column of leaves is blank, blank, blank, 9, blank, blank, blank.
Mathematics
2 answers:
marishachu [46]3 years ago
6 0

Answer:

its b i think

Step-by-step explanation:

Setler79 [48]3 years ago
5 0

Answer:

The answer is C

Step-by-step explanation:

got it right on edge

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What is the area of rectangle ABCD?
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Answer:

240

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Read 2 more answers
Consider the following hypothesis test: H0: LaTeX: \mu_1-\mu_2=0μ 1 − μ 2 = 0 Ha: LaTeX: \mu_1-\mu_2\ne0μ 1 − μ 2 ≠ 0 The follow
Pavel [41]

Answer:

z=\frac{104-\bar 106}{\sqrt{\frac{8.4^2}{80}+\frac{7.6^2}{70}}}}=-1.53

Step-by-step explanation:

Data given and notation

\bar X_{1}=104 represent the mean for the sample 1

\bar X_{2}=106 represent the mean for the sample 2

\sigma_{1} =8.4 represent the population standard deviation for the sample 1

\sigma_{2}=7.6 represent the population standard deviation for the sample 2

n_{1}=80 sample size for the group 1

n_{2}=70 sample size for the group 2

z would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the means for the two groups are the same, the system of hypothesis would be:

H0:\mu_{1}-\mu_{2} =0

H1:\mu_{1} -\mu_{2} \neq 0

If we analyze the size for the samples both are greater than 30 and we know the population deviations so for this case is better apply a z test to compare means, and the statistic is given by:

z=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the statistic

First we need to calculate the mean and deviation for each sample, after apply the formulas (2) and (3) we got the following results:

And with this we can replace in formula (1) like this:

z=\frac{104-\bar 106}{\sqrt{\frac{8.4^2}{80}+\frac{7.6^2}{70}}}}=-1.53

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The cross-sectional areas of a triangular prism and a right cylinder are congruent. The triangular prism has a height of 10 unit
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