Point B has coordinates (3,2). The x-coordinate of point A is -1. The distance between point A and point B is 5 units. What
are the possible coordinates of point A?
2 answers:
The possible coordinates of point A is (-1,-1)
Answer:
(-1, -1)
Step-by-step explanation:
A (-1,y) & B (3,2)
the distance between A and B =
√(3+1)²+(2-y)² = 5
(3+1)² + (2-y)² = 5²
4²+ (2-y)²=25
(2-y)²= 25-16
(2-y)²= 9
2-y=3
y = -1
point A (-1,-1)
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Answer:
Step-by-step explanation:
<u>It is assumed the angles A and C are congruent:</u>
- 3x + 40 = x + 50
- 3x - x = 50 - 40
- 2x = 10
- x = 5
m∠A = 3*5 + 40 = 55°
let the number of sides be n.
Thus,
(n-2)x180=330
n-2=1.83
n=3.83
Rounding off we have, n=4.
Thus the total number of side is 4.
-3(6-10v-5v)
=-3(6-15v)
=-18+45v
-18+45v is the final answer.
It is the bottom right one because the amount he walked has to be greater than 200
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