Please explain thoroughly.

Point I is on line segment HJ. Given I J equals 3X +3, HI equals 3X-1, and HJ equals 3X +8, determine the numerical length of HJ

Nezavi [6.7K]

Answer:

Step-by-step explanation:

3x + 3 + 3x - 1 = 3x + 8

6x + 2 = 3x + 8

3x + 2 = 8

3x = 6

x = 2

HJ= 3(2) + 8 =6 + 8 = 14

HI= 3(2) - 1 = 6 - 1 = 5

IJ = 3(2) + 3 = 6 + 3 = 9

4 0

2 years ago

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In basketball you score 2 points for a field goal and 1 point for a free throw. Suppose that you have scored at least 3 points i

olga55 [171]

2x+y>3 describes the low end, presuming that you have defined to mean the number of field goals and to mean the number of free throws. yet your best game was 15, so the values must also satisfy 2x+y

4 0

3 years ago

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The approximate height, h, in meters, traveled by golf balls hit with two different clubs over a horizontal distance of d meters

inna [77]

Answer:

a) 100 metres

b) 10 metres

Step-by-step explanation:

Given: the approximate height, h, in meters, travelled by golf balls hit with two different clubs over a horizontal distance of d meters is given by the functions: $h=-0.002d^2+0.3d\,,\,h=-0.004d^2+0.5d$

To find: distances when the ball is at the same height when either of the clubs are used. Also, to find this height

Solution:

(a)

$-0.002d^2+0.3d=-0.004d^2+0.5d\\d(-0.002d+0.3)=d(-0.004d+0.5)\\-0.002d+0.004d=0.5-0.3\\0.002d=0.2\\d=\frac{0.2}{0.002}=100\,\,metres$

(b)

Put d = 100 in $h=-0.002d^2+0.3d$

$h=-0.002(100)^2+0.3(100)\\=-20+30\\=10\,\,metres$

4 0

3 years ago

Describe any domain restrictions that make sense for each of these scenarios: The price of a stock fluctuates several times thro

mrs_skeptik [129]

Answer:

a) Restriction: days of the year (a discrete time)

b) The time the ball is on the air: t = 0, until the balls touchs the ground (any real value from t = 0 to t when the ball hits the ground)

c) Any positive real value: x ≥ 0

Explanation:

The domain is the set of elements that can be inputs of the function.

1. The price of a stock fluctuates several times throughout the year as a function of time.

The input variable is the time through out the year.

If you assume that the fluctuaion is recorded once a day, and not every second, the logical assumption is that the time is a day of the year.

Thus, the restricion is the days of the year.

You could represent them in different forms, like DD/MM/YY, or even as a number from 1 to 365 if it covers just one year.

2. A ball is hit into the air by a baseball player, rises until it reaches its highest point, and then falls into left field.

The domain is the time the ball is on the air, which may be any real value from t = 0, until the balls touchs the ground.

It is not restricted to integer numbers.

3. The volume of a spherical balloon increases as the balloon is blown up and decreases as air is let out of it.

The inputs of the function are amounts of air, which may be measured as number of moles.

The number of moles can be any real value equal or greater than zero.

Thus, the domain is the positive real values x ≥ 0.

8 0

3 years ago

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QUESTION 1 The driving distance for the top 100 golfers on the PGA tour is between 284.7 and 310.6 yards.Assume that the driving

GarryVolchara [31]

Answer:

$P(X>300)$

And we can find this probability with the complement rule:

$P(X>300)= 1-P(X$

Step-by-step explanation:

For this case we define the random variable X ="driving distance for the top 100 golfers on the PGA tour" and we know that:

$X \sim Unif (a=284.7, b=310.6)$

And for this case the probability density function is given by:

$f(x) =\frac{1}{310.6 -284.7} =0.0386 , 284.7 \leq X \leq 310.6$

And the cumulative distribution function is given by:

$F(x) =\frac{x-284.7}{310.6-284.7} , 284.7 \leq X \leq 310.6$

And we want to find this probability:

$P(X>300)$

And we can find this probability with the complement rule:

$P(X>300)= 1-P(X$

6 0

3 years ago