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2 years ago

Least:

Mathematics

1 answer:

-Dominant- [34]2 years ago

5 0

Least- 2

Greatest- 12

Median- 7

Lower Q- 4

Upper Q- 8

Range-10

IQR- 4

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Which choice is equivalent to the quotient below shown here when x>0?

qwelly [4]

Answer:

Choice B is correct

Step-by-step explanation:

The given radical division can be expressed in the following form;

$\frac{\sqrt{16x^{3} } }{\sqrt{8x} }$

Using the properties of radical division, the expression can be expressed in the following form;

$\sqrt{\frac{16x^{3} }{8x} }=\sqrt{2x^{2} }$

Simplifying further yields;

$\sqrt{2x^{2} }=\sqrt{2}*\sqrt{x^{2} }=x\sqrt{2}$

Choice B is thus the correct alternative

5 0

3 years ago

Read 2 more answers

Consider a bell-shaped symmetric distribution with mean of 16 and standard deviation of 1.5. Approximately what percentage of da

fredd [130]

Answer: 95.45 %

Step-by-step explanation:

Given : The distribution is bell shaped , then the distribution must be normal distribution.

Mean : $\mu=\ 16$

Standard deviation : $\sigma= 1.5$

The formula to calculate the z-score :-

$z=\dfrac{x-\mu}{\sigma}$

For x = 13

$z=\dfrac{13-16}{1.5}=-2$

For x = 19

$z=\dfrac{19-16}{1.5}=2$

The p-value = $P(-2$

$0.9772498-0.0227501=0.9544997\approx0.9545$

In percent, $0.9545\times100=95.45\%$

Hence, the percentage of data lie between 13 and 19 = 95.45 %

6 0

3 years ago

Whats equivalent expression to 48j+36 with __(4j+__)

Stells [14]

12(4j+3)

because both are divisible by 12

6 0

3 years ago

Read 2 more answers

getting home from trick or treat celia and emma counted their candies. half of celias candies is equal to 2/3 of emmas candies.

blagie [28]

Candies with celias and emmas is 60 and 45 respectively.

<u>Solution:</u>

Given, Getting home from trick or treat celia and emma counted their candies. Half of celias candies is equal to 2/3 of emmas candies.

They had a total of 105 candies altogether.

We have to find how many candies did each of them have.

Let the number of candies with celias be n, then number of candies with emma will be 105 – n.

Now according to given condition.

$\begin{array}{l}{\frac{1}{2} \times \text { celias candies count }=\frac{2}{3} \times \text { emmas candies count }} \\\\ {\rightarrow \frac{1}{2} \times n=\frac{2}{3} \times(105-n)} \\\\ {\rightarrow 3 \times n=2 \times 2 \times(105-n)} \\\\ {\rightarrow 3 \times n=2 \times 2 \times(105-n)} \\\\ {\rightarrow 3 n=4(105-n)} \\\\ {\quad \rightarrow 3 n=420-4 n} \\\\ {\rightarrow 3 n=420-4 n} \\\\ {\rightarrow 3 n+4 n=420} \\\\ {\rightarrow 7 n=7 \times 60} \\\\ {\rightarrow n=60}\end{array}$

Hence, candies with celias and emmas is 60 and 45 respectively.

4 0

3 years ago

4 9/10 divided by 2 3/5

lora16 [44]

<span>4 9/10 divided by 2 3/5

</span>4 9/10 = 49/10
2 3/5 = 13/5

so
(49/10) / (13/5)
=49/10 * 5/13
= 49/26
or
= 1 23/26

8 0

3 years ago