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Ivenika [448]
2 years ago
8

Least:

Mathematics
1 answer:
-Dominant- [34]2 years ago
5 0
Least- 2

Greatest- 12

Median- 7

Lower Q- 4

Upper Q- 8

Range-10

IQR- 4
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Simplify the following expression. 2x-5(2x-7y+3)+(-8)
neonofarm [45]
<span>Equation at the end of step  1  :</span> (2x - 5 • (2x - 7y + 3)) + -8<span> :</span>Pulling out like terms :3.1     Pull out like factors :


  -8x + 35y - 23  =   -1 • (8x - 35y + 23) 

     Final result : -8x + 35y - 23
4 0
3 years ago
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Which of the following is the solution to the following solution of inequality x+2y&lt;4 3x-y&gt;2
mezya [45]
What are the possible answers?

5 0
2 years ago
Graph the linear equation x= - 5​
Grace [21]

Answer:

that would be a vertical line (parallel to the y axis) that passes through -5 on the X axis

Step-by-step explanation:

just a straight line that goes through x = -5. if you're still confused it would also go through the point (-5, -5) a straight vertical line

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2 years ago
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Consider the given function and the given interval. f\(x\) = (x - 7)**2 text(, ) [5 text(, ) 11] (a) Find the average value fave
Jet001 [13]

a. f has an average value on [5, 11] of

f_{\rm ave}=\displaystyle\frac1{11-5}\int_5^{11}(x-7)^2\,\mathrm dx=\frac{(x-7)^3}{18}\bigg|_5^{11}=\frac{4^3-(-2)^3}{18}=4

b. The mean value theorem guarantees the existence of c\in(5,11) such that f(c)=f_{\rm ave}. This happens for

(c-7)^2=4\implies c-7=\pm2\implies c=9\text{ or }c=5

8 0
3 years ago
A circle is described by the equation x2 + y2 + 14x + 2y + 14 = 0. What are the coordinates for the center of the circle and the
Alexandra [31]
Hello :
<span>x² + y² + 14x + 2y + 14 = 0
(x²+14x)+(y²+2y)+14=0
(x²+2(7)(x) +7²) -7² +( y²+(2)(1)y+1²)-1² +14 = 0
(x+7)² +(y+1)² = 6²
the center : (-7,-1) and </span><span>length of the radius is : 6</span>

4 0
2 years ago
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