Answer:
The total power radiated by the sun is 3.71×10^26W
Explanation:
The Earth is spherical in shape
Therefore, Area = 4πr^2 = 4×3.143×(1.489×10^11)^2 = 2.79×10^23m^2
Power radiated by the Sun = solar radiation on Earth × Area = 1330W/m^2 × 2.79×10^23m^2 = 3.71×10^26W
Answer: a. Place the object on one side of a lever at a known distance away from the fulcrum. Place known masses on the other side of the fulcrum so that they are also paced on the lever at known distance from the fulcrum. Move the known masses to a known distance such that the lever is in static equilibrium.
d. Place the object on the end of a vertically hanging spring with a known spring constant. Allow the spring to stretch to a new equilibrium position and measure the distance the spring is stretched from its original equilibrium position.
Explanation:
The options are:
a. Place the object on one side of a lever at a known distance away from the fulcrum. Place known masses on the other side of the fulcrum so that they are also paced on the lever at known distance from the fulcrum. Move the known masses to a known distance such that the lever is in static equilibrium.
b. Place the object on a surface of negligible friction and pull the object horizontally across the surface with a spring scale at a non constant speed such that a motion detector can measure how the objects speed as a function of time changes.
c. Place the object on a surface that provides friction between the object and the surface. Use a surface such that the coefficient of friction between the object and the surface is known. Pull the object horizontally across the surface with a spring scale at a nonconstant speed such that a motion detector can measure how the objects speed as a function of time changes.
d. Place the object on the end of a vertically hanging spring with a known spring constant. Allow the spring to stretch to a new equilibrium position and measure the distance the spring is stretched from its original equilibrium position.
Gravitational mass simply has to do with how the body responds to the force of gravity. From the options given, the correct options are A and D.
For option A, by balancing the torque, the mass can be calculated. Since the known mass and the distance has been given here, the unknown mass can be calculated.
For option D, here the gravitational force can be balanced by the spring force and hence the mass can be calculated.
Answer:
0.1 L
Explanation:
From the question given above, we obtained the following data:
Initial volume (V₁) = 0.05 L
Initial Pressure (P₁) = 207 KPa
Final pressure (P₂) = 101 KPa
Final volume (V₂) =?
We can obtain the new volume (i.e the final volume) of the gas by using the Boyle's law equation as illustrated below:
P₁V₁ = P₂V₂
207 × 0.05 = 101 × V₂
10.35 = 101 × V₂
Divide both side by 101
V₂ = 10.35 / 101
V₂ = 0.1 L
Thus, the new volume of the gas is 0.1 L
The object’s mass will be 600 grams on the moon. If you meant it’s weight, it will be 1/6 that of on Earth while on the moon.
Answer:
Force exerted by the lighter block on the heavier block is 6.63 N
Explanation:
Given Data
F = 80N
m = 1kg
M = 11kg
Solution:
*We assume that there is no friction
Calculating the acceleration of the system
a = 
a = 
a = 
a = 6.67m
Let's write the Equation of Motion of the heavier block
= F - 
Ma = F -
force exerted by the lighter block on the heavier block is calculated as
= F - Ma
= 80 - (11 x 6.67)
= 6.63 N
