If the Amplitud is 11×2=22cm and the wave was in shm then we can get the wavelength as 11×2=22s.
From the wave equation,
v=fλ Where v⇒speed
f⇒frequency and
λ⇒Wavelength
And we know that;
f=1/T
f = 1/4 =0.25 Hz
∴v = 0.25 ×22 = 5.5 cm/s
Since we know know the speed of the object we can get its time it takes from (0-6.5) cm.
v = fλ = λ/T
∴T = λ/v
= 6.5/5.5
= 1 2/11
= 1.181818s
The time taken for the object <span>to move from x = 0.0 cm to x = 6.5 cm is </span>1.181818s
Answer:
A
Step-by-step explanation:
Answer:
25
Step-by-step explanation:
Since triangle DBC is isosceles, angles DBC and DCB must be congruent. Angle BDC is 40 so the sum of the measures of the aforementioned angles must be 180 - 40 = 140; divide that by two and you get that the measure of angle DBC is 70. Angles DBC and ABD are supplementary, as they lie on a straight line, so we can deduce the measure of angle DBA is 180 - 70 = 110. The measure of angle DAB is 180 minus the measures of angle DBA and ADB, we figured out angle DBA is 110 degrees and the problem tells us angle ADB is 45 degrees, so we can subtract to get the measure of angle DAB to be 180 - (110 + 45) = 25.
Answer:
f(g(x)) = 2x +(-5)
Step-by-step explanation:
Put the argument value into the function and simplify the result.
f(g(x)) = f(x -3) = 2(x- 3) +1 = 2x -6 +1
f(g(x)) = 2x +(-5)
If she does 10 a day she will do 520 after 52 weeks
