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Evgen [1.6K]
3 years ago
10

Please help me! Which graph represents the equation below? If you don’t know, please do not answer. Thank you so much!

Mathematics
1 answer:
Irina18 [472]3 years ago
4 0

Answer: b

Step-by-step explanation:

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Reduce to lowest term. 2x^2- 18/x^2+4x-21​
Dovator [93]

Answer:

\frac{2(x+3)}{x+7}

Step-by-step explanation:

Given

\frac{2x^2-18}{x^2+4x-21} ← factorise numerator and denominator

2x² - 18 ( factor out 2 from each term )

= 2(x² - 9) ← difference of 2 squares

= 2(x - 3)(x + 3)

and

x² + 4x - 21 = (x + 7)(x - 3) , then

= \frac{2(x-3)(x+3)}{(x+7)(x-3)} ← cancel common factor (x - 3) on numerator/ denominator

= \frac{2(x+3)}{x+7}

6 0
3 years ago
Work out the size of angle x.
Vlad [161]

Answer:

First: 105

Second: 65

Third: 133

Fourth: 129

Fifth: 60

6 0
3 years ago
What is the equation of the asymptotes?
alexandr1967 [171]
Vertical Asymptotes:
x
=
7
x
=
7
Horizontal Asymptotes:
y
=
2
y
=
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No Oblique Asymptotes
3 0
3 years ago
Write the quadratic equation whose roots are
maks197457 [2]
The quadratic equation y = ax^2 +bx+c can be written in the form:
y = a(x-p)(x-q)
Where p and q are the roots of the equation.
Given p = 4, q = -2, a = 3, the quadratic will look like this:
y = 3(x-4)(x+2)
Finally, distribute and combine like terms to put it in standard form.
y = 3(x^2 - 4x+2x -8) \\  \\ y = 3(x^2 -2x-8) \\  \\ y = 3x^2 -6x -24
5 0
4 years ago
triangle ABC has the vertices A, (-6,2) B (-9,1), C (1,-6). What would be the vertices of ABC' after a reflection across the x-a
brilliants [131]

Answer:

see explanation

Step-by-step explanation:

Under a reflection in the x- axis

a point (x, y) → (x, - y), hence

A(- 6, 2) → A'(- 6, - 2)

B(- 9, 1) → B'(- 9, - 1)

C(1, - 6) → C'(1, 6)

7 0
4 years ago
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