Answer:
csc θ =
/6
sec θ =
/7
tan θ = 6/7
Step-by-step explanation:
The first thing to do will be to compute the length of the hypotenuse using the Pythagoras theorem;
6^2 +7^2 = hypotenuse^2
hypotenuse = 
csc θ = 1/sinθ
sinθ = opposite side/hypotenuse
= 6/
csc θ =
/6
sec θ = 1/cosθ
cosθ = adjacent side/hypotenuse
sec θ = hypotenuse/adjacent side
=
/7
tan θ = Opposite side/adjacent side
= 6/7
Answer:
3:36 PM
Step-by-step explanation:
Let fraction (y) of the people that heard the rumor , the differential equation that is satisfied by the by y is,

Solving the differential equation,
![y(t) = \frac{y_{o}}{[y_{o} + (1 + y_{o})e^{-kt}]}](https://tex.z-dn.net/?f=y%28t%29%20%3D%20%5Cfrac%7By_%7Bo%7D%7D%7B%5By_%7Bo%7D%20%2B%20%281%20%2B%20y_%7Bo%7D%29e%5E%7B-kt%7D%5D%7D)
The total number of inhabitants of the town = 2000
The number of people that heard the rumor = 160
At 8 AM, let t = 0,

= 0.08
By noon, half of the town as heard the rumor.
Then,

Therefore,
![\frac{1}{2} = \frac{0.08}{[0.08 + (1 - 0.08)e^{-4k}]}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%3D%20%5Cfrac%7B0.08%7D%7B%5B0.08%20%2B%20%281%20-%200.08%29e%5E%7B-4k%7D%5D%7D)
![\frac{0.08}{[0.08 + 0.92e^{-4k}]} = \frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B0.08%7D%7B%5B0.08%20%2B%200.92e%5E%7B-4k%7D%5D%7D%20%3D%20%5Cfrac%7B1%7D%7B2%7D)




k ≈ 0.06106
Calculating time, t when y(t) = 90%
⇒ y(t) = 0.9
![\frac{0.08}{[0.08 + 0.92e^{-0.06106t}]} =0.9](https://tex.z-dn.net/?f=%5Cfrac%7B0.08%7D%7B%5B0.08%20%2B%200.92e%5E%7B-0.06106t%7D%5D%7D%20%3D0.9)





t = 7.59 hours
⇒ 7 hours 36 minutes
From 8 A.M. plus 7 hours 36 minutes = 3:36 PM
At 3:36 PM will 90% of the population have heard the rumor
Step-by-step explanation:
Scores of Australia in all four matches starting from 1st 208, 192, 241, 203 respectively.
Similarly, scores of Pakistan in all four matches starting from 1st 102, 202, 360, 276 respectively.
The avg of Pakistan in one match = (102+202+360+276)/4 = 235
The avg of Australia in one match = (208+192+241+203)/4= 211
Since, the avg score of Pakistan is more than that of Australia, Pakistan performed better.
X<2 or x>=2
the answer is D, all real numbers
x can be less than 2 OR x greaterthan/equal to 2
Answer:
range of scores on final exam student get B is 90 to 100
Step-by-step explanation:
given data
Psychology 101 score = 66
average of his midterm = between 78 and 90
maximum = 100 points
to find out
range of scores on final exam student get B
solution
we consider here lowest marks need in final = x
so average at two marks should be
equation is
average marks = 0.5 × ( mid term marks + final marks ) .................1
put here value
78 = 0.5 × ( 66 + x )
x = 90
and
90 = 0.5 × ( 66 + x )
x = 114
so range 90 to 114
but maximum marks is 100 so
range of scores on final exam student get B is 90 to 100