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Dennis_Churaev [7]
3 years ago
14

What is the volume of the cube shown below? V = s×s×s

Mathematics
1 answer:
babymother [125]3 years ago
3 0
15.6 would be the volume.
2 1/2^3
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(x, y) = ( cos 45, sin 45) =

=\text{ (}\frac{\sqrt[]{2}}{2}\text{ , }\frac{\sqrt[]{2}}{2}\text{ )}

The correct option is A

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The points plotted below are on the graph of a polynomial. In what range of
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Write an appropriate direct variation equation if y = 18 when x = 2
Sergeu [11.5K]

Answer:

y=9x

Step-by-step explanation:

we know that

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3 years ago
The length of AB-----is 15 centimeters. A dilation with a scale factor of 0.4 is applied. What is the length of the image of ​ A
ss7ja [257]
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4 years ago
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Q5.Jumbo is standing on top of a cliff looking at a speed boat out at sea.The vertical of the cliff from the base (sea level) to
Leni [432]

Answer:

A) 150 m

B) 180.28 m

Step-by-step explanation:

A) In order to find the horizontal distance from the base of the cliff to the speed boat, use the Pythagorean theorem to calculate the length of the missing side.

We are told that one of the sides is 80 m and the hypotenuse is 170 m. Therefore,

  • a² + b² = c²
  • (80)² + b² = (170)²
  • b² = 170² - 80²
  • b² = 22500
  • b = 150

The horizontal distance between the base of the cliff and the boat is 150 m.

B) Now, the side that was 80 m is now 100 m (includes the height that the helicopter is above Jumbo). The horizontal distance remains the same, 150 m, but the hypotenuse is different. Solving for the hypotenuse will give us the distance between the helicopter and the speed boat.

  • (100)² + (150)² = c²
  • 32500 = c²
  • 180.28 = c

The distance between the helicopter and the speed boat is 180.28 m.

8 0
3 years ago
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