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Dennis_Churaev [7]
3 years ago
14

What is the volume of the cube shown below? V = s×s×s

Mathematics
1 answer:
babymother [125]3 years ago
3 0
15.6 would be the volume.
2 1/2^3
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Y=1/4x−2y=−2x+3 help solve problem.
8_murik_8 [283]

Answer:

  (x, y) = (2 2/9, -1 4/9)

Step-by-step explanation:

Equate the values of y and solve for x.

  1/4x -2 = -2x +3

  (2 1/4)x = 5 . . . . . . . . add 2+2x to both sides

  x = 20/9 = 2 2/9 . . . multiply by 4/9

  y = -2(2 2/9) +3 = -4 4/9 +3 . . . . substitute for x in the second equation

  y = -1 4/9

The solution is x = 2 2/9, y = -1 4/9.

7 0
3 years ago
PLZ HELP Simplify the rational expression. State any excluded values. 2x/-5x+x^2
Bas_tet [7]
(2x/-5x)+x^2
(x(2)/(x(-5))+x^2

(-2/5)+x^2, the x values cancel in numerator and denominator and simplify to -2/5
6 0
3 years ago
Read 2 more answers
please help i don't understand this one i appreciate anyone who helps :) Solve for x. 7x - 3/8 = 6x -
svet-max [94.6K]

Answer:

x = 3/8

Step-by-step explanation:

6 0
3 years ago
For every boy in an advanced math course there are 3 girls who are taking the course.
Nutka1998 [239]

Answer:

If 32 students are enrolled in the course, there would be 24 girls.

Step-by-step explanation:

Given that For every boy in an advanced math course there are 3 girls who are taking the course.

It means if there are four students in the class. There would be 3 girls and 1 boy. Thus, 75% of the students are girls.

Given that there are 32 students enrolled in the course.

so

75% of 32 = 75/100 × 32

                 = 24

Thus, if 32 students are enrolled in the course, there would be 24 girls.

7 0
3 years ago
Suppose you have a cache of radium, which has a half-life of approximately 1590 years. how long would you have to wait for 1/5 o
lubasha [3.4K]
<span>You would have to wait 318 years for 1/5 (20%) of the Radium to disappear. 1590 is the point where half of the Radium would decay, so if you take 20% of that, it would equate out to 318 years. Radium has a long half life!</span>
4 0
4 years ago
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