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nataly862011 [7]
3 years ago
11

Plsss help me ( I put a picture up )

Mathematics
2 answers:
Artist 52 [7]3 years ago
6 0
Answer is the third one

The ratio of Dutch rabbits to all rabbits 5:8
Minchanka [31]3 years ago
3 0
I'm pretty sure the 3rd one is right, use a calculator
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If disposable income is $20 trillion, taxes are $6 trillion, and transfers are $4 trillion, then income is $_____ trillion. Plea
Serjik [45]

Answer:

c) $22 trillion.

Step-by-step explanation:

We have been given that disposable income is $20 trillion, taxes are $6 trillion, and transfers are $4 trillion. We are asked to find income in trillions.

\text{Disposable income}=\text{Income}+\text{Transfers}-\text{Taxes}

\$20=\text{Income}+\$4-\$6, where each amount is in trillions.

\$20=\text{Income}-\$2

\$20+\$2=\text{Income}-\$2+\$2

\$22=\text{Income}

Therefore, the income is $22 trillion.

7 0
4 years ago
Pleasee help me with this problemm
iragen [17]
(_/18+2_/3)^(2

=(3_/2^(2 + (2)(2_/3)(3_/2) + 2_/3^(2)

=18+ 12_/6 +12

=30+12_/6

hope this helps

3 0
3 years ago
Read 2 more answers
On a coordinate plane, triangle J K L has points (negative 2, 1), (0, 3), and (2, negative 1). Reflect the figure over the line
svetlana [45]

Answer:

J'(2, 1)

K'(0, 3)

Step-by-step explanation:

On a coordinate plane, coordinates of the points J, K and L are (-2, 1), (0, 3) and (2, -1) respectively.

If we reflect these points over the line x = 0 or y-axis, rule to be followed is

(x, y) → (-x, y)

Only sign of x coordinates get changed while y coordinates remain the same.

Following this rule coordinates of the images of J' and K' will be

J(-2, 1) → J'(2, 1)

and K(0, 3) → K'(0, 3)

6 0
3 years ago
Read 2 more answers
1.Un número complejo multiplicado por su conjugado da siempre:
algol13
B. 2+5i dis the answer
8 0
3 years ago
Read 2 more answers
Find all possible values of x in the similar triangles pqr stu
antoniya [11.8K]
If triangles PQR and STU are similar then PQ corresponds to ST and PR corresponds to SU. Therefore, PQ/ST=PR/SU
Considering that, PQ= 7-x, ST= 13-x, PR= x²+5 and SU= x² +20
therefore, (7-x)/(13-x)= (x²+5)/(x²+20) 
               cross multiplying,
         7x² +140-x³+20x =13x²+65-x³-5x
combining the like terms,
          6x² +15x -75=0
          solving for x,
    x = 5/2 or -5 
5 0
3 years ago
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