When you have something like this, all you need to do is substitute the values, the last is for what value of x
For the first one;
((x^2+1)+(x-2))(2)
(x^2+x-1)(2)
(2)^2+(2)-1
4+2-1
5
For the second one;
((x^2+1)-(x-2))(3)
(x^2-x+3)(3)
(3)^2-(3)+3
9-3+3
9
For the last one;
3(x^2+1)(7)+2(x-2)(3)
3((7)^2+7)+2((3)-2)
3(49+7)+2(3-2)
3(56)+2(1)
168+2
170
Answer:
Tom's balance at the end of month 5 = 1,871.77
Step-by-step explanation:
a = 1600
ar = 1664
ar² = 1730.56
common ratio, r = ar/a
= 1664/1600
= 1.04
r = 1.04
what will toms balance be at the end of month 5
Month 5 = ar⁴
= 1600 * 1.04⁴
= 1600 * 1.16985856
= 1,871.773696
Approximately 1,871.77
Tom's balance at the end of month 5 = 1,871.77
Step 1: 654.75-15.00= $639.75
Therefore the club made $639.75
14.6 is the constant because no matter how many hours she will work (that number could change) it will always be a linear growth of 14.6.