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ryzh [129]
3 years ago
15

The following is an example of the ____________

Mathematics
2 answers:
Roman55 [17]3 years ago
5 0

Answer:

D.Associative Property

Step-by-step explanation:

Alja [10]3 years ago
4 0

Answer:

D. Accociative Property

Step-by-step explanation:

You switched around the parenthesis!

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-2x+5=4x-7 solve for x. Show all work
Neko [114]

Answer:

2=x

Step-by-step explanation:

-2x+5=4x-7

+2x     +2x

5=6x-7

+7     +7

12=6x

/6

2=x

7 0
3 years ago
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PLEASE HELP THIS IS TIMED!!!
ANTONII [103]

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its c. 1/4

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Which star has a similar surface temperature to our sun?
xenn [34]

Answer: I believe it is yellow star?

Step-by-step explanation:

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3 years ago
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A center has a center at X(4, -3) and a point on the circle is W(8, 0). What is the location of Y on the diameter WY?
igor_vitrenko [27]

Answer: (0, -6)

Step-by-step explanation:

The center is the midpoint of the diameter, meaning that the coordinates of Y must be (0, -6).

7 0
2 years ago
The radius of a spherical balloon is measured as 20 inches, with a possible error of 0.03 inch. Use differentials to approximate
soldi70 [24.7K]

Answer:

a) V = 33510.322\,in^{3}, b) A_{s} = 5026.548\,in^{2}, c) \% V = 0.450\,\%, \%A_{s} = 0.300\,\%.

Step-by-step explanation:

The volume and the surface area of the sphere are, respectively:

V = \frac{4}{3}\pi \cdot r^{3}

A_{s} = 4\pi \cdot r^{2}

a) The volume of the sphere is:

V = \frac{4}{3}\pi \cdot (20\,in)^{3}

V = 33510.322\,in^{3}

b) The surface area of the sphere is:

A_{s} = 4\pi \cdot (20\,in)^{2}

A_{s} = 5026.548\,in^{2}

c) The total differentials for volume and surface area of the sphere are, respectively:

\Delta V = 4\pi\cdot r^{2}\,\Delta r

\Delta V = 4\pi \cdot (20\,in)^{2}\cdot (0.03\,in)

\Delta V = 150.796\,in^{3}

\Delta A_{s} = 8\pi\cdot r \,\Delta r

\Delta A_{s} = 8\pi \cdot (20\,in)\cdot (0.03\,in)

\Delta A_{s} = 15.080\,in^{2}

Relative errors are presented hereafter:

\%V = \frac{\Delta V}{V}\times 100\%

\%V = \frac{150.796 \,in^{3}}{33510.322\,in^{3}}\times 100\,\%

\% V = 0.450\,\%

\% A_{s} = \frac{\Delta A_{s}}{A_{s}}\times 100\,\%

\% A_{s} = \frac{15.080\,in^{2}}{5026.548\,in^{2}}\times 100\,\%

\%A_{s} = 0.300\,\%

4 0
3 years ago
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