3 years ago

In how many ways can a teacher arrange 6 students in the front row of a classroom with a total of 20 students?

1 answer:

5 0

The concept of the question above is Permutation where in we are to arrange to arrange the 6 students from which there are 20 students. This is the "permutation of 20 taken 6" or 20P6. The numerical value of the permutation is equal to 27907200.

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nasty-shy [4]

Answer:

something

Step-by-step explanation:

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3 0

3 years ago

Can somebody help me with this please?

Svetach [21]

Multiply both sides by -4/7
$x = 40 \times ( \frac{ - 4}{7} ) \\ x = \frac{ - 160}{7}$

7 0

3 years ago

A: -27<br> B: -32<br> C: -45<br> D: -101 <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D" id="TexFormula1" title="\frac{

kolezko [41]

$- 25 \: + 13 \: = - 12 \\ - 12 \times 8 = - 96 \\ - 96 \div 3 = - 32 \\ - 32 = p$

p = B

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3 years ago

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emmasim [6.3K]

I think it’s 3 not sure!

7 0

2 years ago

-4(5x-3)+15 is equivalent to

podryga [215]

Answer:

-20x+27

Step-by-step explanation:

-4(5x-3)+15 Distribute First

-20x+12+15 Simplify

-20x+27 All Done!

8 0

3 years ago