Question

A circle is centered at (0,0) and has a radius of 2\sqrt{3}

Answer 1

Answer:

Outside of the circle

Step-by-step explanation:

First, find the equation of the circle by plugging in the center point and radius:

(x - h)² + (y - k)² = r²

(x - 0)² + (y - 0)² = ($2\sqrt{3}$)²

x² + y² = 12

Plug in point M to see where it lies:

x² + y² = 12

(-3)² + (2)² = 12

9 + 4 = 12

13 ≠ 12

Since this statement is false, point M lies outside of the circle.