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gregori [183]
3 years ago
7

Plz answer all ALLL AND PLZ ANSWER CORRECT

Mathematics
1 answer:
timofeeve [1]3 years ago
5 0

Answer yiu can buy spaghetti corn fries cake

Step-by-step explanation: the main dish should come out with a

lot of spaghetti so that is a good choice you should be able to share with a least 3 people witch leave 5 more people they us come out with a lot of corm where I live so that would be good for at least 4 people and the fries could be share amd the cake should let everyone share.

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Identify whether the function graphed has an odd or even degree and a positive or negative leading coefficient.
Shtirlitz [24]

Answer:

odd degree and positive leading coefficient

Step-by-step explanation:

From the graph , we can see that when x goes to infinity , y goes to infinity

As x--> ∞, y--> ∞ (As x increases the value of y increases on the positive side)

we can see that when x goes to -infinity , y goes to -infinity

As x--> -∞, y--> -∞ (As x decreases the value of y decreases on the negative side)

When x--> ∞, y--> ∞   and x--> -∞, y--> -∞

The leading coefficient is positive  and largest exponent is odd

So the graph has odd degree and positive leading coefficient


8 0
3 years ago
What is the x-intercept and y-intercept of the linear equation 3x-6y=2
sukhopar [10]

Answer:

The x-intercept is 2/3 and the y-intercept is -1/3

Step-by-step explanation:

In order to find this, we need to note that the x-intercept is the value of x, when y = 0. So we plug in y = 0 and see what the x value is.

3x - 6y = 2

3x - 6(0) = 2

3x = 2

x = 2/3

The y-intercept is the opposite. It is the y value when x = 0. So we do the same with the other term.

3x - 6y = 2

3(0) - 6y = 2

-6y = 2

y = -2/6

y = -1/3

8 0
3 years ago
Probabilities with possible states of nature: s1, s2, and s3. Suppose that you are given a decision situation with three possibl
amm1812

Answer:

1. P(s_1|I)=\frac{1}{11}

2. P(s_2|I)=\frac{8}{11}

3. P(s_3|I)=\frac{2}{11}

Step-by-step explanation:

Given information:

P(s_1)=0.1, P(s_2)=0.6, P(s_3)=0.3

P(I|s_1)=0.15,P(I|s_2)=0.2,P(I|s_3)=0.1

(1)

We need to find the value of P(s₁|I).

P(s_1|I)=\frac{P(I|s_1)P(s_1)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}

P(s_1|I)=\frac{(0.15)(0.1)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}

P(s_1|I)=\frac{0.015}{0.015+0.12+0.03}

P(s_1|I)=\frac{0.015}{0.165}

P(s_1|I)=\frac{1}{11}

Therefore the value of P(s₁|I) is \frac{1}{11}.

(2)

We need to find the value of P(s₂|I).

P(s_2|I)=\frac{P(I|s_2)P(s_2)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}

P(s_2|I)=\frac{(0.2)(0.6)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}

P(s_2|I)=\frac{0.12}{0.015+0.12+0.03}

P(s_2|I)=\frac{0.12}{0.165}

P(s_2|I)=\frac{8}{11}

Therefore the value of P(s₂|I) is \frac{8}{11}.

(3)

We need to find the value of P(s₃|I).

P(s_3|I)=\frac{P(I|s_3)P(s_3)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}

P(s_3|I)=\frac{(0.1)(0.3)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}

P(s_3|I)=\frac{0.03}{0.015+0.12+0.03}

P(s_3|I)=\frac{0.03}{0.165}

P(s_3|I)=\frac{2}{11}

Therefore the value of P(s₃|I) is \frac{2}{11}.

4 0
3 years ago
*Absurd answers will be reported* Can the fraction 12/30 be reduced/simplified? If it can, what can it be reduced by?
Fynjy0 [20]

Answer:

divided by 3 12/30 = 4/10 = 2/5

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
On a coordinate plane, an exponential growth function approaches y = 0 in the second quadrant and goes through points (negative
mojhsa [17]

Answer:

(2,18)

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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