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ss7ja [257]
3 years ago
6

HELP ME RN PLEASE Which of the following expressions is equivalent to the expression below?

Mathematics
1 answer:
kari74 [83]3 years ago
4 0

Answer:

i dont know what the answers are but if one of them says 14x+6 then thats correct.

Step-by-step explanation:

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I need this for a test Plz. I need this ASAP
Darina [25.2K]

Answer:

B

Step-by-step explanation:

cos(a) is AC/AB and sin(B) is AC/AB

6 0
3 years ago
Yusra's dog is overweight. The vet says the dog needs to lose 7 pounds to get down to the desirable weight of 45 pounds. How muc
irga5000 [103]

Answer:

the dog weighs 52lb

7 0
2 years ago
Find the greatest common factor of 8m 3 and 6m 4
irina [24]

ANSWER

2{m}^{3}

EXPLANATION

The expressions are

8 {m}^{3}  =  {2}^{3}  \times  {m}^{3}

and

6 {m}^{4}  = 2 \times 3 {m}^{4}

The greatest common factor is the product the least powers of the common factors.

= 2 {m}^{3}

5 0
3 years ago
Please help with 6 and 7
Maru [420]

Answer:

6a) i- 2hrs 36mins  ii- 3hrs 12mins

b) car A≈ 76.9km/h  car B≈ 62.5km/h

c)------

7a) 35km

b) car A=75km  car B=60km

c) 30km

d) car A≈36mins  car B≈48mins

Step-by-step explanation:

6a) Using the graph follow the lines until they finish then go downwards until you get to the x-axis. The x-axis is going up by 12mins for each square.

b) Using the answer from a, you divide 200km by the time.

For car A 2hrs 36mins becomes 2.6 because 36mins/60mins=0.6

∴ car A: 200/2.6≈ 76.92km/h

For car B 3hrs 12mins becomes 3.2 because 12mins/60mins=0.2

∴ car B: 200/3.2≈ 62.5km/h

7a) Using the graph go down from where the line of car A finished to meet car B. The y-axis is going up by 5km for each square.

b) Starting from the x-axis at 1 hour go upwards to see where you meet the car B line (60km) and car A line(75km). (sorry if that does not really make sense).

c) Difference from car A line to car B:

155km-125km=30km

d) Going across from 50km meet car A line and go down to see it has been travelling for approx. 36mins. Then continue across to car B line, go down to see it reached 50km at approx. 48mins.

Hope this helps.

5 0
4 years ago
by 14 1 4 each week for a number of weeks, w . He writes the expression 20(14) 20 ( 1 4 ) w to find the amount of radioactive su
erastovalidia [21]

Answer:

1/2 ^w : decay factor after w weeks

hope this helps

Step-by-step explanation:


8 0
3 years ago
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