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jasenka [17]
3 years ago
7

The Sanchez family ordered 3 children's meals and an adult meal at a restaurant.

Mathematics
2 answers:
Gekata [30.6K]3 years ago
6 0

Answer:

5

Step-by-step explanation:

3x + 12 = 27 3x = 15 x = 5

MrRa [10]3 years ago
4 0

Answer:

5 dollars per child

Step-by-step explanation:

The total cost was 27.

The adult meal was 12 dollars.

27- 12 = 15

there are three children

15 ÷ 3 = 5

therefore the kids meals were $5.00 per kid.

You might be interested in
Which of the following is a composite number?<br><br> A)47<br><br> B)91<br><br> C)101<br><br> D)131
Varvara68 [4.7K]
91 = 7*13 is a composite number. It has factors other than itself and 1.
3 0
3 years ago
An article suggests that a poisson process can be used to represent the occurrence of structural loads over time. suppose the me
kirill115 [55]

Answer:

a) \lambda_1 = 2*2 = 4

And let X our random variable who represent the "occurrence of structural loads over time" we know that:

X(2) \sim Poi (4)

And the expected value is E(X) = \lambda =4

So we expect 4 number of loads in the 2 year period.

b) P(X(2) >6) = 1-P(X(2)\leq 6)= 1-[P(X(2) =0)+P(X(2) =1)+P(X(2) =2)+...+P(X(2) =6)]

P(X(2) >6) = 1- [e^{-4}+ \frac{e^{-4}4^1}{1!}+ \frac{e^{-4}4^2}{2!} +\frac{e^{-4}4^3}{3!} +\frac{e^{-4}4^4}{4!}+\frac{e^{-4}4^5}{5!}+\frac{e^{-4}4^6}{6!}]

And we got: P(X(2) >6) =1-0.889=0.111

c)  e^{-2t} \leq 2

We can apply natural log in both sides and we got:

-2t \leq ln(0.2)

If we multiply by -1 both sides of the inequality we have:

2t \geq -ln(0.2)

And if we divide both sides by 2 we got:

t \geq \frac{-ln(0.2)}{2}

t \geq 0.8047

And then we can conclude that the time period with any load would be 0.8047 years.

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

P(X=x)=\lambda e^{-\lambda x}

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution"

Solution to the problem

Let X our random variable who represent the "occurrence of structural loads over time"

For this case we have the value for the mean given \mu = 0.5 and we can solve for the parameter \lambda like this:

\frac{1}{\lambda} = 0.5

\lambda =2

So then X(t) \sim Poi (\lambda t)

X follows a Poisson process

Part a

For this case since we are interested in the number of loads in a 2 year period the new rate would be given by:

\lambda_1 = 2*2 = 4

And let X our random variable who represent the "occurrence of structural loads over time" we know that:

X(2) \sim Poi (4)

And the expected value is E(X) = \lambda =4

So we expect 4 number of loads in the 2 year period.

Part b

For this case we want the following probability:

P(X(2) >6)

And we can use the complement rule like this

P(X(2) >6) = 1-P(X(2)\leq 6)= 1-[P(X(2) =0)+P(X(2) =1)+P(X(2) =2)+...+P(X(2) =6)]

And we can solve this like this using the masss function:

P(X(2) >6) = 1- [e^{-4}+ \frac{e^{-4}4^1}{1!}+ \frac{e^{-4}4^2}{2!} +\frac{e^{-4}4^3}{3!} +\frac{e^{-4}4^4}{4!}+\frac{e^{-4}4^5}{5!}+\frac{e^{-4}4^6}{6!}]

And we got: P(X(2) >6) =1-0.889=0.111

Part c

For this case we know that the arrival time follows an exponential distribution and let T the random variable:

T \sim Exp(\lambda=2)

The probability of no arrival during a period of duration t is given by:

f(T) = e^{-\lambda t}

And we want to find a value of t who satisfy this:

e^{-2t} \leq 2

We can apply natural log in both sides and we got:

-2t \leq ln(0.2)

If we multiply by -1 both sides of the inequality we have:

2t \geq -ln(0.2)

And if we divide both sides by 2 we got:

t \geq \frac{-ln(0.2)}{2}

t \geq 0.8047

And then we can conclude that the time period with any load would be 0.8047 years.

3 0
3 years ago
Convert to standard form.<br> y-5=-3(x+2)​
Paul [167]

Answer:

Step-by-step explanation:

y-5=3(x+2)

y-5=3x+6

y-5-6=3x+6-6

y-1=3x

7 0
3 years ago
The Capacity of a 1 cm cube is 1 mL. How many 1 cm ice cubes do you need to melt to fill a 1.5 L jar.
Svetach [21]

1500 ice cubes need to fill 1.5 L jar

Solution:

1 cm = 1 ml

Capacity of ice cube = 1 cm

                                   = 1 ml

Capacity of jar = 1.5 L

1 L = 1000 ml

1.5 L = 1.5 × 1000

       = 1500 ml

Capacity of jar = 1500 ml

$\text{Number of ice cubes} =\frac{\text{Capacity of ice cube}}{\text{Capacity of jar}}

                                $=\frac{1500}{1}

                                = 1500

Therefore 1500 ice cubes need to fill 1.5 L jar.

8 0
3 years ago
Three oblique pyramids have the same regular square base. Which one has a volume of 15 cubic units if the area
Verizon [17]

Answer:

B

Step-by-step explanation:

5 0
3 years ago
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